Find three consecutive integers such that the sum of the first and twice the second is 80 minus three times the third
1 answer:
Answer:
The three consecutive integers are 12, 13, 14.
Step-by-step explanation:
Encode the question in an equation. We are given two facts: (1) the three integers are consecutive, and (2) they relate to each other through a sum.
Pick any of the integers (first, second, or third) and call it n. Then write the two others correspondingly in terms of n. I pick the middle one as n, so the three consecutive integers are (n-1), n, (n+1). That's (1). As for (2), here is the fact:
Lo and behold, one equation with one unknown! Easy to solve for n to give us the middle integer, n:
The three consecutive integers are 12, 13, 14.
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Answer:
Area of the counter top is .
Step-by-step explanation:
Given:
Length of the Counter top = 18 feet
Width of the counter top = 3 feet
We need to find the area of the counter top is square meter;
Solution:
Now we need to find the area of the counter top is square meter.
But given data is in feet so we will first convert feet into meters.
1 foot = 0.305 meter.
So 18 feet = Number of meters in 18 feet.
By Using Unitary method we get;
Number of meters in 18 feet =
Length of the Counter top = 5.49 m
Also 3 feet = Number of meters in 3 feet.
Again Using Unitary method we get;
Number of meters in 3 feet =
Width of the counter top = 0.915 m
Now we know that;
Area of the counter top can be calculated by multiplying Length of the counter top with width of the counter top.
framing in equation form we get;
Area of the counter top =
Rounding up to 2 decimals we get;
Area of the counter top =
Hence Area of the counter top is .