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aniked [119]
4 years ago
10

What is the value of q? 50 55 100 60

Mathematics
1 answer:
Andrei [34K]4 years ago
4 0
This is a inscribed angle, so that the angle is 1/2 the measurement of the arc length.

You are trying to find q°

100/2 = 50

q° = 50°

hope this helps
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At the beginning of the day the stock market goes down 4014 40 1 4 points and stays at this level for most of the day. At the en
Stels [109]

Answer:

<h2>124.51%</h2>

Step-by-step explanation:  

In this problem, we are expected to solve for the percentage change, given the opening  point and the closing point

given that the low is 4014

and the high is  9012

the formula to calculate the percentage change is given as

%change= (high-low)/low*100

substituting our given data we have

%change= (9012-4014)/4014*100

%change= (4998)/4014*100

%change= (1.2451)*100

%change= 124.51%

The total change in the stock market from the beginning of the day to the end of the day is 124.51%

7 0
3 years ago
The base of the 37 foot ladder is 9 feet from the wall of a building. will the top of the ladder reach a window ledge 35 feet ab
AnnZ [28]

Answer:

The answer to your question is Yes.

Step-by-step explanation:

The math in this problem is that we need to use the Pythagorean theorem to solve it. Pythagorean theorem is part of trigonometry a branch of Maths.

Data

base = 9 ft                      

length = 37 ft

height = ?

Pythagorean theorem

                                     c² = a² + b²

length = c

base = a

height = b

                                   37² = 9² + b²

-Solve for b

                                    b² = 37² - 9²

-Simplify

                                    b² = 1369 - 81

                                    b² = 1288

-Result

                                   b = 35.88

-Conclusion

The ladder will reach a height higher than 35 ft.  

8 0
4 years ago
Solve for b to the nearest hundredth:
lawyer [7]
The right answer is B (b=-0.243)
7 0
3 years ago
How do I simplify the expression 7^0+7^2 over (7^3)^2
AlekseyPX

\frac{7^0+7^2}{(7^3)^2}=\frac{1+49}{7^6} = \frac{50}{117649}

Ok done. Thank to me :>

7 0
2 years ago
Use the surface integral in​ Stokes' Theorem to calculate the circulation of the field Bold Upper F equals x squared Bold i plus
Tom [10]

Stokes' theorem says the integral of the curl of \vec F over a surface S with boundary C is equal to the integral of \vec F along the boundary. In other words, the flux of the curl of the vector field is equal to the circulation of the field, such that

\displaystyle\iint_S\nabla\times\vec F\cdot\mathrm d\vec S=\int_C\vec F\cdot\mathrm d\vec r

We have

\vec F(x,y,z)=x^2\,\vec\imath+4x\,\vec\jmath+z^2\,\vec k

\implies\nabla\times\vec F(x,y,z)=4\,\vec k

Parameterize the ellipse S by

\vec s(u,v)=\dfrac{u\cos v}{\sqrt5}\,\vec\imath+\dfrac{u\sqrt5\sin v}4\,\vec\jmath

with 0\le u\le1 and 0\le v\le2\pi.

Take the normal vector to S to be

\dfrac{\partial\vec s}{\partial\vec u}\times\dfrac{\partial\vec s}{\partial\vec v}=\dfrac u4\,\vec k

Then the flux of the curl is

\displaystyle\iint_S4\,\vec k\cdot\dfrac u4\,\vec k\,\mathrm dA=\int_0^{2\pi}\int_0^1u\,\mathrm du\,\mathrm dv=\boxed{\pi}

4 0
3 years ago
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