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3 years ago

I need to know how to set up this problem. Please help

Mathematics

1 answer:

ELEN [110]3 years ago

7 0

your total would be $10 and you have 1 variable. so it would be ($2x) for the pounds of veggies, plus the 3.50 for the basket, equals $10. then solve for X from there

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Math:

Dahasolnce [82]

Answer:

a) $x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$ , $x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$ , b) $x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$ , $x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$

Step-by-step explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:

$\sqrt{3}\cdot \csc x - 2 = 0$

$\sqrt{3} \cdot \left(\frac{1}{\sin x} \right) - 2 = 0$

$\sqrt{3} - 2\cdot \sin x = 0$

$\sin x = \frac{\sqrt{3}}{2}$

$x = \sin^{-1} \frac{\sqrt{3}}{2}$

Value of x is contained in the following sets of solutions:

$x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$

$x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$

b) The equation must be simplified first:

$\cos x + 1 = - \cos x$

$2\cdot \cos x = -1$

$\cos x = -\frac{1}{2}$

$x = \cos^{-1} \left(-\frac{1}{2} \right)$

Value of x is contained in the following sets of solutions:

$x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$

$x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$

7 0

3 years ago

HELP QUICK<br> Remove grouping symbols and combine like terms.<br> 4a2 - 3[2b - 3b(b - 1)]

kvasek [131]

Answer:
4a^2 - 15b + 9b^2

Step by step explanation:

8 0

2 years ago

Read 2 more answers

What two numbers add up to equal 6, but multiply to equal 13?

KatRina [158]

4 and 2 equal up to be 6

4 0

2 years ago

Read 2 more answers

Round 43,951,842 to the nearest hundred-thousand

GrogVix [38]

I think the answer would be 44,000,000 because if you roundthe 951 it goes to 1,000

4 0

3 years ago

Read 2 more answers

Choose the correct simplification of (4x − 3)(3x2 − 4x − 3).

tester [92]

$(4x - 3)(3x^2 - 4x - 3)$

$=4x\cdot \:3x^2+4x\left(-4x\right)+4x\left(-3\right)-3\cdot \:3x^2-3\left(-4x\right)-3\left(-3\right)$

$=4x\cdot \:3x^2-4x\cdot \:4x-4x\cdot \:3-3\cdot \:3x^2+3\cdot \:4x+3\cdot \:3$

$\mathrm{Simplify}\:4x\cdot \:3x^2-4x\cdot \:4x-4x\cdot \:3-3\cdot \:3x^2+3\cdot \:4x+3\cdot \:3:\quad 12x^3-25x^2+9$

$=12x^3-25x^2+9$

8 0

3 years ago