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o-na [289]
3 years ago
8

write the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to 2x+y=-5. include your work in

your final answer.
Mathematics
2 answers:
Readme [11.4K]3 years ago
6 0
Parallel to 2x+y=-5
2x+y-2x=-5-2x
y=-2x-5
y=mx+b
Slope: m=-2

As the line is parallel must have the same slope:
m=-2
And it has an x-intercept of 2: when x=2, y=0→Point: P1=(2,0)=(x1,y1)
x1=2, y1=0

y-y1=m(x-x1)
y-0=(-2)(x-2)
y=-2x+4
In standard form:
y+2x=-2x+2x+4
2x+y=4

Answer: The equation of the line, in standard form, that passes through the origin and is parallel to x+y=6 is x+y=0
garik1379 [7]3 years ago
3 0


The general equation of the line is ⇒⇒⇒ y = mx + c
where: m is the slope of the line ,  c is constant
The given line is 2x + y = -5 ⇒⇒⇒ ∴ y = -5 - 2x
The slope of the given line = -2 
The required line is parallel to the given line . So, it have the same slope
∴ m = -2
∴ The general equation of the line will be ⇒⇒⇒ y = -2x + c
to find c we need a point on the line
<span>x-intercept of 2 which mean the line pass through (2,0)
</span><span>
</span><span>substitute with (2,0) to find C
</span><span>
</span><span>∴ 0 = -2*2 +c ⇒⇒⇒ c = 4
</span><span>
</span><span>
</span><span>
</span><span>The required line is ⇒⇒⇒⇒ y = -2x + 4
</span><span>
</span><span>OR                        2x + y = 4
</span>



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