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gladu [14]
3 years ago
6

I need help with this question, I will give brainliest

Mathematics
2 answers:
PolarNik [594]3 years ago
5 0

Answer:

3

Step-by-step explanation:

trust me

ahrayia [7]3 years ago
3 0

Answer:

2. f(x) = -4/3 x + 8/3

Step-by-step explanation:

To find a function's inverse, switch y and x, then solve for y.

y = -3/4 x + 2

x = -3/4 y + 2

3/4 y = -x + 2

y = -4/3 x + 8/3

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Figures ABCD and PQRS are parallelogram find x and y (lengths are in metres) Part i and ii.​
STatiana [176]

Step-by-step explanation:

For 1st question

In a parm ABCD

5x - 4 = 16 ( being opposite sides of parallelogram)

5x = 16 + 4

5x = 20

x = 20 / 5

x = 4

3y + 1 = 22 (being opposite sides of parallelogram)

3y = 22 -1

3y = 21

y = 21 / 3

y = 7

For second question

In parm PQRS

Diagonals bisect each other so

x + 4 = 12

x = 12 - 4

x = 8

x + y = 32

8 + y = 32

y = 32 - 8

y = 24

Hope it will help :)❤

8 0
3 years ago
Ludwig borrowed $700,000 for a period of 2 years. His interest rate is 10%. How much interest will Ludwig pay in all?
harkovskaia [24]
By yearly interest or monthly? Yearly: he pays 840000 monthly: 2380000 sorry it’s so long just tryna help a bruthu or sister out I didn’t check yo username
5 0
3 years ago
Which of these relations on the set {0, 1, 2, 3} are equivalence relations? If not, please give reasons why. (In other words, if
Delicious77 [7]

Answer:

(1)Equivalence Relation

(2)Not Transitive, (0,3) is missing

(3)Equivalence Relation

(4)Not symmetric and Not Transitive, (2,1) is not in the set

Step-by-step explanation:

A set is said to be an equivalence relation if it satisfies the following conditions:

  • Reflexivity: If \forall x \in A, x \rightarrow x
  • Symmetry: \forall x,y \in A, $if x \rightarrow y,$ then y \rightarrow x
  • Transitivity: \forall x,y,z \in A, $if x \rightarrow y,$ and y \rightarrow z, $ then x \rightarrow z

(1) {(0,0), (1,1), (2,2), (3,3)}

(3) {(0,0), (1,1), (1,2), (2,1), (2,2), (3,3)}

The relations in 1 and 3 are Reflexive, Symmetric and Transitive. Therefore (1) and (3) are equivalence relation.

(2) {(0,0), (0,2), (2,0), (2,2), (2,3), (3,2), (3,3)}

In (2), (0,2) and (2,3) are in the set but (0,3) is not in the set.

Therefore, It is not transitive.

As a result, the set (2) is not an equivalence relation.

(4) {(0,0), (0,1), (0,2), (1,0), (1,1), (1,2), (2,0), (2,2), (3,3)}

(1,2) is in the set but (2,1) is not in the set, therefore it is not symmetric

Also, (2,0) and (0,1) is in the set, but (2,1) is not, rendering the condition for transitivity invalid.

5 0
3 years ago
Can we say that the larvae of the lady bugs will eat approximately 500 fleas per day
levacccp [35]
Well sure, go w that and see what you get
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3 years ago
Practice isolating the variable to solve equations with
bulgar [2K]

Answer:

9 =6x

Step-by-step explanation:

We know this is the answer because the -4x was cancelled out left to the equal sign, and 2x has now become 6x after adding 4x.

5 0
3 years ago
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