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sweet [91]
4 years ago
11

Ts marsvectorcalc6 2.5.033. ask your teacher my notes question part points submissions used let f: double-struck r4 → double-str

uck r and c(t): double-struck r → double-struck r4. suppose ∇f(1, 1, π, e6) = (0, 1, 3, −9), c(π) = (1, 1, π, e6), and c'(π) = (18, 13, 0, 1). find d(f ∘
c.dt when t = π.
Mathematics
1 answer:
tia_tia [17]4 years ago
7 0
By the chain rule,

\dfrac{\mathrm d(f\circ c)}{\mathrm dt}=\nabla f(c(t))\cdot\dfrac{\mathrm dc}{\mathrm dt}

When t=\pi, the derivative has a value of

\nabla f(c(\pi))\cdot c'(\pi)=\nabla f(1,1,\pi,e^6)\cdot(18,13,0,1)=(0,1,3,-9)\cdot(18,13,0,1)=0+13+0-9=4
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A math textbook costs $60.00. The number of students who need the book is represented by x. The total cost of purchasing books f
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Step-by-step explanation:

X=students

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3 years ago
Which function has the higher rate of change over the interval [0,3]
Oksana_A [137]
Since the average rate of change of a function is the slope of the associated line we have already done the work in the last problem. That is, the average rate of change of from 3 to 0 is 1. That is, over the interval [0,3], for every 1 unit change in x, there is a 1 unit change in the value of the function.
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3 years ago
What is the vertex and axis of symmetry for y=4x^2-12x+9?
VLD [36.1K]

Answer:

axis of symmetry   x=3/2

vertex  (3/2, 0)

Step-by-step explanation:

to find the axis of symmetry we use h = -b/2a

where ax^2 + bx+c


h = -(-12)/2(4)

h= 12/8

h = 3/2

the axis of symmetry is x = 3/2

the x coordinate of the vertex is h x=3/2

to find k, the y coordinate of the vertex, substitute x=3/2 into the equation

y=4x^2-12x+9

y=4(3/2) ^2-12(3/2)+9

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the vertex (3/2, 0)

4 0
3 years ago
Which represents the reflection of f(x) = √x over the y-axis?
Reika [66]

Answer:

the first table you provided would be the reflection of f(x)=sqrtx

Step-by-step explanation:

if you graph the sqrt-x then you will see the exact same graph as the fourth picture provided. this is a reflection across the y axis as the y values do not change but the x values become negative as the graph moves to the next quadrant

3 0
4 years ago
What is the slope of a line perpendicular to the line y = −14x – 1?
mash [69]

Answer:

<h2>         m = ¹/₁₄</h2>

Step-by-step explanation:

y=m₁x+b₁   ⊥   y=m₂x+b₂   ⇔    m₁×m₂ = -1

{Two lines are perpendicular if the product of theirs slopes is equal -1}

y = -14x - 1   ⇒   m₁ = -14

-14×m₂ = -1        ⇒    m₂ = ¹/₁₄

So, the slope of a line perpendicular to the line y = -14x - 1 is m = ¹/₁₄

5 0
3 years ago
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