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Art [367]
2 years ago
5

The population of a city on April 15, 1915, was 47,175. During the period between March 1 and July 1, 1915, 1,325 new cases of s

mallpox occurred in the city. Of these cases, 642 persons were ill with smallpox according to surveillance reports on June 1, 1915. The monthly incident rate (per 1,000) of active cases of influence for the 4-month period was:
Mathematics
1 answer:
Norma-Jean [14]2 years ago
7 0

Answer:

the incidence rate is 28.47

Step-by-step explanation:

The computation of the monthly incident rate of active cases is shown below:

Incidence rate is

= 1325 ÷  (47175 - 642) × 1000

= (1325 ÷ 46533 ) ×  1000

= 28.47

hence, the incidence rate is 28.47

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8/9= 16/18 and 3/11=6/22
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Ira wants to determine the fast food restaurant preferred by the majority of twelve year olds in his town. Which sample populati
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3 years ago
8th Grade Math Equation. Please help! I accept any type of help!
muminat

Hello from MrBillDoesMath!

Answer:

Positive x-intercept =  + sqrt(3)

Negative x-intercept = - sqrt(3)


Discussion:

Generally, the x-intercept of a function g(x) occurs where g(x) = 0. In our case this is

g(x) = 0   =>

3x^2 - 9 = 0     =>                         (add 9 to both sides of the equation)

3 x^2      = 9    =>                         (divide both sides by 3)

x^2 = 9/3 = 3  =>

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Positive x-intercept =  + sqrt(3)

Negative x-intercept = - sqrt(3)



Thank you,

MrB

5 0
3 years ago
Please help out thanksssss yallllllll!!!!!!!!!
Mila [183]

Answer:

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4 0
2 years ago
Read 2 more answers
66.
Naddik [55]

Answer:  530.66 units²

<u>Step-by-step explanation:</u>

Area_{(circle)}=\pi r^2\qquad and\qquad r=\dfrac{diameter}{2}\\\\\\\implies Area_{(circle)}=\pi \bigg(\dfrac{diameter}{2}\bigg)^2\\\\\\\text{It is given that the diameter = 26:}\\A=\pi\bigg(\dfrac{26}{2}\bigg)^2\\\\\\.\quad =\pi \cdot 13^2\\\\\\.\quad =169\pi\\\\\\.\quad =\large\boxed{530.66}

3 0
3 years ago
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