Answer:
C
Step-by-step explanation:
When completing the square, we essentially want to create a perfect square trinomial by adding a constant.
If we have the following expression:
And we want to complete the square, we will need to divide the b-coefficient by half and then square it.
Thus, the added term should be:
In the given equation, we have:
The b term here is 8. Therefore:
The value we would add would be 16.
The answer is C.
Further notes:
To complete the square, add 16 like mentioned earlier. However, we also need to subtract 16 to balance things out:
The expression inside the parentheses is now a perfect square trinomial. Factor it:
And we are done!
Hi there!
To find the indefinite integral, we must integrate by parts.
Let "u" be the expression most easily differentiated, and "dv" the remaining expression. Take the derivative of "u" and the integral of "dv":
u = 4x
du = 4
dv = cos(2 - 3x)
v = 1/3sin(2 - 3x)
Write into the format:
∫udv = uv - ∫vdu
Thus, utilize the solved for expressions above:
4x · (-1/3sin(2 - 3x)) -∫ 4(1/3sin(2 - 3x))dx
Simplify:
-4x/3 sin(2 - 3x) - ∫ 4/3sin(2 - 3x)dx
Integrate the integral:
∫4/3(sin(2 - 3x)dx
u = 2 - 3x
du = -3dx ⇒ -1/3du = dx
-1/3∫ 4/3(sin(2 - 3x)dx ⇒ -4/9cos(2 - 3x) + C
Combine:
<span>5(3x^3)^3-2(3x^3)
=</span><span>5(3^3 x^9) - 6x^3
= 135x^9 - 6x^3
= 3x^3 (45x^6 - 2)</span>
Answer:
im pretty sure its pink
Step-by-step explanation:
Answer:
In order from least to greatest: 0.25, 3 ⅜, 3 <span>⅖</span>;
Or, write as: 0.25 < 3 ⅜ < 3 ⅖ .
___________________________________
Explanation:
0.25 = ¼ l (less than "1"); the lowest of the three given values.
The remaining two values have the same whole number of 3, and a fraction:
3 <span>⅖ ;</span> and 3 ⅜.
The least common multiples among the denominators of the fraction values is 40. ⅖ = ?/40 ; 5*? =40? 5* 8 = 40, so 2*8 = 16;
Thus, ⅖ = 16/40, and 3 ⅖ = 3 16/40. 3/8 = ?/40? 8*5 =40; so 3*5 = 15 ; thus ⅜ = 15/40; and
and 3 ⅜ = 3 15/40.
3 15/40 is less than than 3 16/40;
as such; 3 ⅜ is less than 3 ⅖.
So, in order from least to greatest: 0.25, 3 ⅜, 3 ⅖;
Or, write as: 0.25 < 3 ⅜ < 3 ⅖ .
