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3 years ago

Sheila bought 10 1⁄2 oz of almonds for $3.36. How much did the almonds cost per ounce?

Mathematics

1 answer:

Marrrta [24]3 years ago

4 0

3.36/10.5 = 0.32

It costs $0.32 an ounce

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If anyone can help me out I would truly appreciate it Please show me step by step

wel

Answer:

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Step-by-step explanation:

Step 1: Define

Identify

0.3y + y/z

y = 10

z = 5

Step 2: Evaluate

Substitute in variables: 0.3(10) + 10/5
Multiply: 3 + 10/5
Divide: 3 + 2
Add: 5

3 0

3 years ago

Please help asap!!!!

igor_vitrenko [27]

Answer:

$m\widehat {MP} =46\degree$

Step-by-step explanation:

By inscribed angle theorem:

$m\angle MQP=\frac{1}{2} \times \widehat {MP}$

$23\degree =\frac{1}{2} \times m\widehat {MP}$

$23\degree \times 2= m\widehat {MP}$

$m\widehat {MP} =46\degree$

7 0

3 years ago

On Sunday, Chris bought 5% of the cans from his grocery store in preparation for hurricane Sandy. If he bought 61 cans, how many

Gelneren [198K]

Answer:

1220 cans

Step-by-step explanation:

Let the number of cans be x

5% of x is 61, solve the equation below for x:

x*0.05 = 61
x = 61/0.05
x = 1220 cans

7 0

3 years ago

If you have 20 oranges and a friend bought 10 more and gave then to you and you bought 10 more and then you divide the oranges f

In-s [12.5K]

Answer:

I guess each friend gets 16 oranges and its gonna be uneven there is gonna be like 1 left over

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

The number of hours a lightbulb burns before failing varies from bulb to bulb. The population distribution of burnout times is s

liubo4ka [24]

ANSWER:

The average burnout time of a large number of bulbs has a sampling distribution that is close to Normal.

STEP-BY-STEP EXPLANATION:

The cental limit theorem states, that id the sample size is large (30 or more), then the sampling distribution of the sample means is approximately normal with mean ц and standar deviation б/ $\sqrt{n}$

Thus the correct answer is the average burnout time of a large number of bulbs has a sampling distribution that is close to Normal.

6 0

3 years ago