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3 years ago

15

You are choosing between two health club. club a offers membership for a fee of $20 plus a monthly fee of $25. club b offers mem

bership for a fee of $35 plus a monthly fee of $18. after how many months will the total cost of each health club be the same!

1 answer:

____ [38]3 years ago

8 0

20+25x=35+18x
x=1 month
x=15/7

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Three fifths of the sum of 13 and 6

Nadya [2.5K]

Answer: 11.4

Step-by-step explanation:

change to numbers $\frac{3}{5} (13+6)$

simplify $\frac{3}{5} (19)\\11.4$

6 0

3 years ago

Simplify negative 5 minus the square root of negative 44 negative 5 minus 4 times the square root of 11 i negative 5 minus 4 i t

Anika [276]

Answer:

$-5-\sqrt{-44}=-5-2\sqrt{11}i$

Step-by-step explanation:

We want to simplify:

$-5-\sqrt{-44}$

We rewrite the expression under the radical sign to obtain:

$-5-\sqrt{4\times11\times -1}$

We split the expression under the radical sign to get:

$-5-\sqrt{4} \times \sqrt{11} \times \sqrt{-1}$

Recall that:

$\sqrt{-1}=i$

This implies that:

$-5-\sqrt{4} \times \sqrt{11} \times \sqrt{-1}=-5-2\sqrt{11}i$

Therefore $-5-\sqrt{-44}=-5-2\sqrt{11}i$

6 0

3 years ago

mr. larsen's third grade class has 22 students, 12 girls and 10 boys. two students must be selected at random to be in the fall

faust18 [17]

The probability that no boys will be chosen is 0.2857

What is probability?

The area of arithmetic called likelihood deals with numerical representations of the chance that an incident can occur or that a press release is true.

Main Body:

Total students =22

total boys = 10

total girls =12

Now we have to chose 2 girls from 12 , so combination is used to select ,

⇒¹²C₂

Also, We have to chose 2 girls from 22 students

so it can be represented as ,

⇒²²C₂

Probability of choosing 2 girls = ¹²C₂/²²C₂

On solving this we will get = 0.2857

Hence the probability is 0.2857

To know more about probability , visit;

brainly.com/question/13604758

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5 0

1 year ago

Find all solutions of the equation: 2cos^2x-cosx=1

Art [367]

If you're using the app, try seeing this answer through your browser: brainly.com/question/3166243

——————————

Solve the trigonometric equation:

$\mathsf{2\,cos^2\,x-cos\,x=1}\\\\ \mathsf{2\,cos^2\,x-cos\,x-1=0}$

Make a substitution:

$\mathsf{cos\,x=t\qquad (-1\le t\le 1)}$

and the equation becomes

$\mathsf{2t^2-t-1=0}$

Rewrite conveniently – t as + t – 2t, and then factor the left-hand side by grouping:

$\mathsf{2t^2+t-2t-1=0}\\\\ \mathsf{t\cdot (2t+1)-1\cdot (2t+1)=0}$

Factor out 2t + 1:

$\mathsf{(2t+1)\cdot (t-1)=0}\\\\ \begin{array}{rcl} \mathsf{2t+1=0}&~\textsf{ or }~&\mathsf{t-1=0}\\\\ \mathsf{2t=1}&~\textsf{ or }~&\mathsf{t=1}\\\\ \mathsf{t=\dfrac{\,1\,}{2}}&~\textsf{ or }~&\mathsf{t=1} \end{array}$

Substitute back for t = cos x:

$\begin{array}{rcl}\mathsf{cos\,x=\dfrac{\,1\,}{2}}&~\textsf{ or }~&\mathsf{cos\,x=1}\\\\ \mathsf{cos\,x=cos\,60^\circ}&~\textsf{ or }~&\mathsf{cos\,x=cos\,0} \end{array}$

Therefore,

$\begin{array}{rcl} \mathsf{x=\pm\,60^\circ+k\cdot 360^\circ}&~\textsf{ or }~&\mathsf{cos\,x=0+k\cdot 360^\circ} \end{array}$

where k is an integer.

Solution set:

$\mathsf{S=\left\{x\in\mathbb{R}:~~x=-\,60^\circ+k\cdot 360^\circ~~or~~x=60^\circ+k\cdot 360^\circ~~or~~x=k\cdot 360^\circ,~~k\in\mathbb{Z}\right\}}$

I hope this helps. =)

3 0

3 years ago

Price-club sells a 12-ounce package of spaghetti noodles for $3.44 and Shop Mart sells a 2-pound box of spaghetti noodles for $8

Eva8 [605]

The unit price per ounce at Price club is $0.29 and the unit price per ounce at Shop Mart is $0.26

Step-by-step explanation:

Price of 12 ounce package at Price Club = $3.44

Unit rate per ounce = $\frac{Price\ of\ package}{Weight\ of\ package}$

Unit rate per ounce = $\frac{3.44}{12} = \$0.29$

Price of 2 pound box at Shop Mart= $8.35

1 pound = 16 ounce

2 pound = 16*2 = 32 ounces

Unit rate per ounce = $\frac{Price\ of\ package}{Weight\ of\ package}$

Unit rate per ounce = $\frac{8.35}{32} = \$0.26$

The unit price per ounce at Price club is $0.29 and the unit price per ounce at Shop Mart is $0.26

Keywords: unit rate, division

Learn more about division at:

#LearnwithBrainly

5 0

3 years ago