Probability that the first card is not a club is 1 minus probability that it is a club. i.e. 1 - 1/4 = 3/4
Probability that the second card is a diamond = 1/4
Probability that the first card is not a club AND the second card is a diamond is 3/4 x 1/4 = 3/16
Its a simultaneous equation:
lets make "x" the used games and "y" the new ones
4x + 2y = 84
6x + y = 78. (multiply this by 2 to cancel out y)
12x + 2y = 156
so now we subtract them:
12x - 4x = 156 - 84
x = 9
used games cost $9
new games cost 78 - 6(9) = $24
Janet has $120 but she already bought 3 NEW games so:
120 - 3(24) = $48 left
48/9 = how many used ones she can buy = 5. something
she can buy 5 used
Answer:
Yes
Step-by-step explanation:
I feel like its yes because x and y share the numbers 1-4
This is a false statement.
When you are solving using square roots, you need to be aware that answers can be both positive and negative. When we solve this, you see there are two possible answers.
x^2 - 9 = 0
x^2 = 9
x = +/- 3
While 3 is an answer, so is -3. If we square either of those numbers, we get 9, which will satisfy the equation.
