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igomit [66]
3 years ago
11

In a group of 55 examinees taking the 50-item test, Rachel obtained the score of 38. This implies that her score is...​

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
4 0

Answer:

she scored 76 percent in the test

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Jackets price is reduced from $25 to $15. by what percentage was the price of the sweater reduced.
Helga [31]

Answer:

40 percent

Step-by-step explanation:

10 / 25 =.4=40%

7 0
3 years ago
Read 2 more answers
On what interval(s) is the graph decreasing? - use interval notation
Anna [14]
The function is decreasing from -6 to -3, that is, on the interval (-6,-3), and again on the interval (1, infinity).  

The function is increasing on (-3,1).

No local or absolute minimum.

(1,4) is an absolute max.
6 0
3 years ago
Given f(x) = (lnx)^3 find the line tangent to f at x = 3
kirill [66]
Explanation

We must the tangent line at x = 3 of the function:

f(x)=(\ln x)^3.

The tangent line is given by:

y=m*(x-h)+k.

Where:

• m is the slope of the tangent line of f(x) at x = h,

,

• k = f(h) is the value of the function at x = h.

In this case, we have h = 3.

1) First, we compute the derivative of f(x):

f^{\prime}(x)=\frac{d}{dx}((\ln x)^3)=3*(\ln x)^2*\frac{d}{dx}(\ln x)=3*(\ln x)^2*\frac{1}{x}=\frac{3(\ln x)^2}{x}.

2) By evaluating the result of f'(x) at x = h = 3, we get:

m=f^{\prime}(3)=\frac{3}{3}*(\ln3)^2=(\ln3)^2.

3) The value of k is:

k=f(3)=(\ln3)^3

4) Replacing the values of m, h and k in the general equation of the tangent line, we get:

y=(\ln3)^2*(x-3)+(\ln3)^3.

Plotting the function f(x) and the tangent line we verify that our result is correct:

Answer

The equation of the tangent line to f(x) and x = 3 is:

y=(\ln3)^2*(x-3)+(\ln3)^3

6 0
1 year ago
What have I done wrong and where please help me
lys-0071 [83]
12x - 18 - 4x -2
12x - 4x = 8x (yours 12x - 4x = 8)
-18 - 2 = -20 (yours -18 -1 = 17)

answer:

8x - 20
6 0
3 years ago
Which points on the wave are the trough and the crest?
Vlad1618 [11]

Answer:

ok

trough is the y

Crest is W

I put a picture for help

6 0
3 years ago
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