I would say that the last one would be the most accurate.
let's firstly convert the mixed fractions to improper fractions and then multiply across.
![\bf \stackrel{mixed}{1\frac{8}{10}}\implies \cfrac{1\cdot 10+8}{10}\implies \stackrel{improper}{\cfrac{18}{10}\implies \cfrac{9}{5}}~\hfill \stackrel{mixed}{5\frac{1}{2}}\implies \cfrac{5\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{11}{2}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{9}{5}\cdot \cfrac{11}{2}\implies \cfrac{9\cdot 11}{5\cdot 2}\implies \cfrac{99}{10}\implies 9\frac{9}{10}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B1%5Cfrac%7B8%7D%7B10%7D%7D%5Cimplies%20%5Ccfrac%7B1%5Ccdot%2010%2B8%7D%7B10%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B18%7D%7B10%7D%5Cimplies%20%5Ccfrac%7B9%7D%7B5%7D%7D~%5Chfill%20%5Cstackrel%7Bmixed%7D%7B5%5Cfrac%7B1%7D%7B2%7D%7D%5Cimplies%20%5Ccfrac%7B5%5Ccdot%202%2B1%7D%7B2%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B11%7D%7B2%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ccfrac%7B9%7D%7B5%7D%5Ccdot%20%5Ccfrac%7B11%7D%7B2%7D%5Cimplies%20%5Ccfrac%7B9%5Ccdot%2011%7D%7B5%5Ccdot%202%7D%5Cimplies%20%5Ccfrac%7B99%7D%7B10%7D%5Cimplies%209%5Cfrac%7B9%7D%7B10%7D)
With what ? I need more instructions
Answer:
No Solution.
Step-by-step explanation:
16-2t=t+9+4t*16-2t=t+9+4t
16-2t=t+9+64t-2t=5t+9
16-2t=9+63t=5t+9
16-2t-63t=9=5t+9
16-65t=9=5t+9
16-65t=9,
65t=16-9
t=7/65
9=5t+9
5t=9-9
5t=0
t=0/5
t=0
It's the distributive property. It takes the equation, 15+10 and finds the greatest common factor of 5. it divides both numbers by 5 and puts the 5 outside of the parentheses.
