Question

a plane rises from take-off and flies at an angle of 6 with the horizontal runway. When it has gained 900 feet, find the distance, to the nearest foot, the plane has flown.

Answer 1

Answer:

$d=8610.1ft$

Step-by-step explanation:

From the question we are told that:

Angle $\theta =6\textdegree$

Height of plane $h=900ft$

Generally the trigonometric equation for distance flown d is mathematically given by

  $sin \theta=\frac{h}{d}$

Therefore

 $d=\frac{h}{sin\theta}$

 $d=\frac{900}{sin6}$

 $d=8610.1ft$