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Veronika [31]
3 years ago
11

What is the solution set for (x-2)<15

Mathematics
1 answer:
Anit [1.1K]3 years ago
3 0
X - 2 < 15:5
x - 2 < 3
x< 3+2
x < 5  the first is the answer
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The function fx) = 5 reflected over the y-axis. Which equations represent the reflected function? Select two
VladimirAG [237]

Answer:

y=5

Step-by-step explanation:

f(x) =5 is a line with the equation y=5

when reflected over the y-axis is still y= 5, because we reflected on to itself.

8 0
3 years ago
choose all expressions that are equal to 28.3. A. 27 + 0.91 + 0.39 B. 0.01 + 28.02 C. 9.9 + 9.8 + 9.6 D. 0.02 + 28 + 0.28 E. 27.
amm1812
The answer is A, D, and E because when you add them up they give you 28.3
7 0
3 years ago
12 = -4(-6x - 3)<br><br> x= <br><br> i made this 19 points please help
7nadin3 [17]

Answer:

0

Step-by-step explanation:

-4 times -6x is 24x and-4 x -3 = 12

isolating 24x on the right side we subtract twelve on the right and on the left to get 24x=0 and 24 divided by zero is 0

7 0
2 years ago
Read 2 more answers
I will mark brainliest!
Gelneren [198K]

Answer:

A

Step-by-step explanation:

It looks like M is composed of all real numbers and that U = R also means its composed of all real numbers. This means that M and U are equal and both are composed of all real numbers.

To define the complement of M, it includes all values which are not in M. However, since M already has all real numbers and U doesn't have any values that M doesn't then the complement is nothing. It is an empty set with no items in it. This means A is the correct answer.

5 0
3 years ago
y=f(x) is odd (f(-x)=-f(x)) and f(x&gt;0) = x^2-5x-12, x is not = to 0. What points does the line f(x)=12 go through.
solmaris [256]
<span>f(x<0)=-f(x>0)=-x^2+5x+12 When x>0, x^2-5x-12=12, x=8, y=12 Therefore, f(x)=12 goes through point (8,12).</span>
5 0
3 years ago
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