The speed of the plane after it encounters the wind is C.285mph
<h3>How to calculate the speed of the plane when it encounters the wind?</h3>
Since the plane takes off from an airport on a bearing of 270° and travels at a speed of 320 mph it's velocity is v = (320cos270°)i + (320sin270°)j
= (320 × 0)i + (320 × -1)j
= 0i - 320j
= - 320j mph
Also, the plane encounters a 35 mph wind blowing directly north. The velocity of the wind is v' = 35j mph
So, the velocity of the plane after it encounters the wind is the resultant velocity, V = v + v'
= -320j mph + 35j mph
= -285j mph
So, the speed of the plane after it encounters the wind is the magnitude of V = |-285j| mph
= 285 mph
So, the speed of the plane after it encounters the wind is C.285mph
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Hello!
So you figure that 7/10-5/10=2/10 that leave you with 1/5 left over. So if you take that into effect, all you have to do it multiply those 3 gallons by 5. Which gives you 15. So, your answer would be 15 gallons.
I hope this helped!
I am, yours most sincerely
SuperHelperThingy
Please see figure for answers
Answer: 3.2808
There are 91.44 centimetres in one yard
Divide 300 by 91.44
A . 2/10 + 5/10= 7/10
B. 3/10 + 4/10= 7/10
C. 6/10 + 1/10 =7/10
