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vredina [299]
3 years ago
5

The answer is A true

Mathematics
1 answer:
irinina [24]3 years ago
7 0

Answer:

Are you asking? Or telling me? Sorry im not sure what you want me to do...--

Step-by-step explanation:

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What is 9 2/3 - 2 8/10
umka21 [38]
9 2/3 - 2 8/10 = 16 13/15
7 0
3 years ago
Is this correct btw I put 1400​
Oxana [17]

Answer: Yes

Step-by-step explanation: The answer of 1400 is correct.

What I did is I found the area of the figure assuming it was a rectangle, then I subtracted the corners that were removed.

1800 - 150 - 100 - 150 = 1400

5 0
3 years ago
Read 2 more answers
720 over P = 9, what's P
snow_tiger [21]

Answer:

80

Step-by-step explanation:

720/P = 9/1

Cross multiply.

9P = 720

P = 720/9

P = 80

8 0
3 years ago
What are two square numbers added together equal 65?
pychu [463]
8 and 1
8 squared is 64 and 1 squared is 1
64 + 1 = 65
Hope this helps :)
7 0
3 years ago
Read 2 more answers
If y-3x=9, 7x+y=25, what is the value of x and y?
lianna [129]

\bold{\rm{Given}}\text{ : If y - 3x = 9, 7x + y = 25, what is the value of x and y}?

\bold{\rm{Solution}} \text{: We'll solve this by substitution method}

\dashrightarrow  y - 3x = 9 \\  \\  \dashrightarrow   \boxed{y = 9 + 3x } \qquad .. \sf eq(1)

\text{we got the value of y now getting the value of x}

\looparrowright 7x + y = 25 \\  \\  \looparrowright 7x = 25 - y \\  \\  \looparrowright  \boxed{x =   \frac{25 - y}{7}} \qquad .. \sf eq(2)

\text{Now, putting y = 9 + 3x in eq(2)}

\hookrightarrow  x =  \frac{25 - y}{7}   \\  \\ \hookrightarrow  x =  \frac{25 - 9 + 3x}{7}  \\  \\ \hookrightarrow  7x =  25 - 9 + 3x \\  \\ \hookrightarrow  7x - 3x =  16 \\  \\ \hookrightarrow  4x = 16 \\  \\ \hookrightarrow  x =  \frac{16}{4}  \\  \\ \star \quad  \boxed{ \green{ \frak{ x = 4}}}

\text{Now we know the value of x, for getting y we need to put x in eq(1)}

: \implies y = 9 + 3x \\  \\   : \implies y = 9 + 3(4) \\  \\  : \implies y = 9 + 12  \\  \\    \star \quad  \boxed{\frak{  \green{y = 21}}}

\text{Hence, values of x and y are} \:  \frak{ \green{4}}  \: \text{and} \:  \frak{ \green{21}} \: \text{respectively}.

4 0
2 years ago
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