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UNO [17]
3 years ago
5

How are real numbers used to describe real-world situations?

Mathematics
1 answer:
Alinara [238K]3 years ago
7 0
Real numbers are all the rational numbers such as -7 and 4/3 and all irrational numbers. Real numbers are used mainly in counting and are used in measurement which is always present in real-world situations. These numbers help us to quantify things around.
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Give EG = 5x+7 EF =5x and FG=2x-7
Len [333]

Answer:

x = 7

42, 35, 7

Step-by-step explanation:

  • EG = 5x+7
  • EF = 5x  
  • FG = 2x-7

Point F is on line segment of EG, therefore EG = EF + FG

  • 5x + 7 = 5x + 2x - 7
  • 2x = 14
  • x = 7

Then

  • EG = 5*7 + 7 = 42
  • EF = 5*7 = 35
  • FG = 2*7 - 7 = 7
7 0
3 years ago
Factor the following 3x + 66y
miv72 [106K]

Answer:

3(x+22y)

Step-by-step explanation:

Because three can be taken from both of them

8 0
3 years ago
A number cube with the numbers 1 through 6 is rolled. What is the probability of the number cube showing an even number or a num
inna [77]

Answer:

Step-by-step explanation:

The correct answer is 5/6 = 83.3%

I really hope this helps!

8 0
3 years ago
Jenny opened a package of screws quickly and many of them spilled on the floor. She needs to organize the fasteners according to
hichkok12 [17]

We have to compare diameters and arrange them in order smallest to greatest

We can see units for option A and B are in square inches so they represents area. So first we will find diameter from area using formula

A = \pi r^{2}

so for choice (A) area is given as 4.375 \times 10^{7}. So plug this in A place in formula and then solve for radius r

4.375 \times 10^{7} = \pi r^{2}

\frac{4.375 \times 10^{7}}{\pi}   = \frac{\pi r^{2}}{\pi}

1.393 \times 10^{7} } =  r^{2}

\sqrt{1.393 \times 10^{7}}  = \sqrt{r^{2}}

3731.76 = r

So screw A will have
diameter = 2 \times r = 2 \times 3731.76 = 7463.52 inches

Similarly for choice (E) area is 1.428 \times 10^{1} = 14.28
so again plug in formula

A = \pi r^{2}

14.28 = \pi r^{2}

\frac{14.28}{\pi}   = \frac{\pi r^{2}}{\pi}

4.5477 =  r^{2}

\sqrt{4.5477}  = \sqrt{r^{2}}

2.13201 = r

So screw E will have
diameter = 2 \times r = 2 \times 2.13201 = 4.26402 inches

So diameters of all screws are as follows:

Screw A: 7463.52 inches
Screw B: 1.5 inches
Screw C: 1\frac{7}{8} =  \frac{1\times 8+7}{8} = \frac{15}{8} = 1.875 inches
Screw D: 0.25 inches
Screw E: 4.26402 inches

Comparing all numbers 7463.52, 1.5, 1.875, 0.25, 4.26402 we can see that smallest number is 0.25, then comes 1.5, then 1.875 and then 4.26402 and then 7463.52

So order from least to greatest will be screw D (0.25), B(1.5), C(1.875), E (4.26402), A (7463.52).

So thats the order D,B,C,E,A and the final answer

6 0
4 years ago
Read 2 more answers
An expression is shown below:
chubhunter [2.5K]
It is irrational and is = to 4√2
3 0
3 years ago
Read 2 more answers
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