Question

4.solve for x and y pls help

Answer 1

Answer:

x = 4$\sqrt{3}$

y = 8$\sqrt{3}$

Step-by-step explanation:

this is a 30-60-90 triangle and the sides have a constant ratio

the side across from the 30°∡ is 1

the side across from the 60°∡ is √3

the side across from the 90°∡ is 2

In this problem we can find 'x' by setting up this proportion:

x/12 = $\sqrt{3}$/1

cross-multiply:

$\sqrt{3}$x = 12

x = 12/$\sqrt{3}$

since we don't like to leave radicals in the denominator, we can multiply both numerator and denominator by $\sqrt{3}$ to get:

12$\sqrt{3}$ ÷ $\sqrt{3}$·$\sqrt{3}$    ($\sqrt{3}$·$\sqrt{3}$ = $\sqrt{9}$, which equals 3)

so we have 12$\sqrt{3}$/3, which is 4$\sqrt{3}$

The 'y' value will be twice the 30° side, so 8$\sqrt{3}$