Your answer would be r = 12/7 ≈ 1.71
Firstly you need to write an equation involving r and t. They tell you that r varies inversely with t, which means r = k/t, where k is some constant.
We can find k by substituting in the values for r and t that they give us:
r = k/t
2 = k/(-6)
-12 = k
Now the equation is r = -12/t. We can then substitute in t as -7 to get the final answer:
r = -12/t
r = -12/(-7)
r = 12/7 ≈ 1.71
I hope this helps!
Answer:
The angles inside a hexagon add up to 720.
105 + 88 + 142 + 140 + 124 + x = 720
720 - (105 + 88 + 142 + 140 + 124) = x
720 - 599 = x
<h2>x = 121</h2>
Answer:
j = 6
Step-by-step explanation:
1. What one needs to know
-Slope-intercept form
The formula of a line in slope-intercept form is;
y = mx + b
Where "m" is the slope. and "b" is the y-intercept.
2. Approach
The slope of the line is given. One has to solve for the y-intercept. Since a point on the line is given, one simply has to substitute in the point on the line and solve for b. The one substitutes in the other point with the unknown in it. One will then solve to find the unknown.
3. Finding "b"
It is given that this line has a slope of , therefore, the equation of the line with the slope would look something like this;
y = x + b
It is given that (-4, -8) is on the line, substitute this point in;
-8 = (-4) + b
Solve;
-8 = (-4) + b
-8 = - 0.8 + b
-7.2 = b
The complete formula of this line is;
y = 0.2(x) - 7.2
( in decimals )
4. Solve of "j"
Point (j, -6) is on this line, substitute it into the formula
y = 0.2(x) - 7.2
-6 = 0.2(j) - 7.2
Inverse operations;
-6 = 0.2(j) - 7.2
+7.2 +7.2
1.2 = 0.2(j)
/0.2 /0.2
6 = j
Answer:
A rectangle
Step-by-step explanation:
A rectangle is one kind of quadrilateral with four right angles. The definition of a rectangle is a shape with four sides and four right angles. This means each angle in a rectangle measures 90 degrees. Another property of a rectangle is that opposite sides are parallel to each other and equal in length.
If the gradient of an equation is equal to 2/7, that will be your answer..