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denpristay [2]
3 years ago
15

Find the area of the polygon XYZ that has its vertices at X(–3, 6), Y(–3, 1), and Z(5, 1).

Mathematics
1 answer:
elixir [45]3 years ago
6 0

Hope you can understand

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A total of 486 tickets were sold for the school play. They were either adult tickets or student tickets. There were 64 fewer sru
padilas [110]

Answer:

Step-by-step explanation:

A=number Adult tickets;S=A+74= number Student tickets

Total tickets=adult tickets + student tickets

724=A+(A+74)

 

724=2A+74 Subtract 74 from each side

650=2A divide each side by 2

325=A ANSWER 1: There were 325 Adult tickets sold

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3 years ago
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hoa [83]
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You subtract 5 1/4 (5.25) - 3 3/4 (3.75) = 1 1/2 (1.5)
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2 years ago
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Each vertical cross-section of the triangular
Blizzard [7]

Answer:

The vertical height is h=3\ units

Step-by-step explanation:

we know that

In the right triangle ABC

see the attached figure

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c^{2}=a^{2}+b^{2}

we have

c=AB=3\sqrt{2}\ units

a=BC=6/2=3\ units

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(3\sqrt{2})^{2}=3^{2}+h^{2}

18=9+h^{2}

h^{2}=18-9=9

h=3\ units

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2 years ago
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So its 7:10am in AZ and I'm bored hbu?
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2 years ago
Solve for x please help me
Mademuasel [1]

x = 51.98

Step-by-step explanation:

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or

x = 21×tan68°

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3 0
2 years ago
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