Find the area of the polygon XYZ that has its vertices at X(–3, 6), Y(–3, 1), and Z(5, 1).

Mathematics

1 answer:

elixir [45]3 years ago

6 0

Hope you can understand

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viktelen [127]

Answer:

just crop it ok

Step-by-step explanation:

I'm not sure ok

8 0

2 years ago

Find the length of a segment with endpoints Y(2, 8) and Z(- 2, 5) .

Andrej [43]

<em>The distance the length of a segment with endpoints Y(2, 8) and Z(-2, 5) is 5 units</em>

<h2>Explanation:</h2>

Endpoints of a Line segments are places where they end or stop. Line segments are named after their endpoints. In this case, those endpoints are Y and Z, so the line segment would be:

$\overline{YZ} \ or \ \overline{ZY}$

To find the length of this segment with endpoints Y(2, 8) and Z(-2, 5), let's use the Distance Formula:

$d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

$Let's \ write: \\ \\ Y(x_{1},y_{1}) \rightarrow Y(2, 8) \\ \\ Z(x_{2},y_{2}) \rightarrow (-2, 5) \\ \\ \\ Substituting: \\ \\ d=\sqrt{(-2-2))^2+(5-8)}^2 \\ \\ d=\sqrt{(-4)^2+(-3)^2} \\ \\ d=\sqrt{16+9} \\ \\ d=\sqrt{25} \\ \\ \boxed{d=5}$