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denpristay [2]
3 years ago
15

Find the area of the polygon XYZ that has its vertices at X(–3, 6), Y(–3, 1), and Z(5, 1).

Mathematics
1 answer:
elixir [45]3 years ago
6 0

Hope you can understand

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The dot plot shows the number of pets owned by the students in jay of class
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Answer:

where is the graph ?

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3 years ago
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1 pt) If a parametric surface given by r1(u,v)=f(u,v)i+g(u,v)j+h(u,v)k and −4≤u≤4,−4≤v≤4, has surface area equal to 1, what is t
natta225 [31]

The area of the surface given by \vec r_1(u,v) is 1. In terms of a surface integral, we have

1=\displaystyle\int_{-4}^4\int_{-4}^4\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv

By multiplying each component in \vec r_1 by 5, we have

\dfrac{\partial\vec r_2(u,v)}{\partial u}=5\dfrac{\partial\vec r_1(u,v)}{\partial u}

and the same goes for the derivative with respect to v. Then the area of the surface given by \vec r_2(u,v) is

\displaystyle\int_{-4}^4\int_{-4}^425\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv=\boxed{25}

8 0
3 years ago
Helpp me asapp with this problem plss will crown brainiest !!!!
Evgen [1.6K]

Answer:

see below

Step-by-step explanation:

Since RT bisects QRS

1/2  QRS = TRS

1/2 ( 9x+214) = -9x+53

Multiply each side by 2

9x +214 = -18x+ 106

Add 18x from each side

9x +214+18x = 106

27x +214 = 106

Subtract 214 from each side

27x = 106-214

27x =-108

Divide by 27

27x/27 = -108/27

x = -4

TRS = -9x+53

     =-9 *-4 +53

     = 36+ 53

    =89

4 0
3 years ago
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Please help with steps:
Nezavi [6.7K]

Answer:

20 25 35 40 50

4 5 7 8 10

step-by-step Explaination:

20÷4=5 so 5 photos every minute

5×5=25

35÷5=7

5×8=40

50÷5=10

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2 years ago
Animals have an exrectory system with a support structure called a
IrinaVladis [17]
<span>Animals have an excretory system with a support structure called a skeleton</span>
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