First you would find the sum of 187.56 and 49.73 which is 237.29 then you subtract this number from 18.65 which is 218.64 that's your answer
Answer:

Step-by-step explanation:
Given
Two rolls of die
one of the outcomes is 6
atleast one is 6
Required
P(E|A)
First, list out the outcome of each


So:

Where:



So:

I just took the test the correct answer is:
Amplitude = 3 feet; 3 period = 16 hours; midline: y = 5.
3. f(-6) = 12+1 =13
f(-2) = 4+1 = 5
f(0) =1
Range {1,5,13}
4. f(-2) = (-2)^3+1 =-7
f(-1) = (-1)^2 +1 =0
f(3) = (3)^3 +1 = 28
Range = {-7,0,28}
5.the sequence is arithmetic
d= -11+19 = 8
an = a1 + d(n-1)
an = -19 +8(n-1)
6.l =w+5
a =l*w
a(w) =(w+5) * w
a(w)= w^2 +5w
f(w) = w^2 +5w
f(8) = 8^2 +5(8)
f(8) = 64 +40
f(8) =104 in^2