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anastassius [24]
3 years ago
15

Y=1/3 x^2+2x+5 what is the minimum value of this equation

Mathematics
1 answer:
sammy [17]3 years ago
3 0

Answer:

Min: (-3,2)

Hope this helps!!

You might be interested in
Find x and y. <br>x - y = 2 <br>3x - y = 12​
omeli [17]

the answer is

X=5

y=3

hope you like it

8 0
2 years ago
PLEASE SOMEONE HELP ME
Julli [10]

Answer:

The answer is 5 times

Step-by-step explanation:

First, we need to read the change in price in 2000 and 2007, from the graph.

So, the change in price in 2000 was $0.14 and in 2007 it was $0.71.

Now, we do the same thing we always do when comparing two values - we divide them. So:

0.71 / 0.14 = 5.07

Of course, we could multiply these values with 100, in order to avoid decimal numbers. Then we would get:

71 / 14 = 5.07

We could also divide this in the form of fractions:

71/100 / 14/100 = 5.07

There are several ways we could divide rational numbers, but the result will always be the same.

Change in price in 2007 was around 5 times greater than the change in 2000.

I hope this helps!!;-)

6 0
3 years ago
16. Hamster Heaven charges an annual fee of $20 plus $2.50 for each day of hamster
Ludmilka [50]

Answer:

hamster heaven

y=20+2.5x

hamster fun world

y=35+x

Step-by-step explanation:

by solving we get

x=10

y=45

by comparing the graph hamster fun world 8s cheaper on the long run

Mark Me Brainliest

8 0
2 years ago
Help me with this one question plz i put a picture below so u can see it
Mkey [24]
4 campers per one canoe

8 0
3 years ago
The Wisconsin Dairy Association is interested in estimating the mean weekly consumption of milk for adults over the age of 18 in
Stolb23 [73]

Answer:

ME = 1.653 *\frac{7.9}{\sqrt{300}}= \pm 0.75

±0.75 ounce

Step-by-step explanation:

Assuming this complete question: The Wisconsin Dairy Association is interested in estimating the mean weekly consumption of milk for adults over the age of 18 in that state. To do this, they have selected a random sample of 300 people from the designated population. The following results were recorded: xbar=34.5 ounces, s=7.9 ounces Given this information, if the leaders wish to estimate the mean milk consumption with 90 percent confidence, what is the approximate margin of error in the estimate?

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=34.5 represent the sample mean

\mu population mean (variable of interest)

s=7.9 represent the sample standard deviation

n=300 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=300-1=299

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,199)".And we see that t_{\alpha/2}=1.653

And the margin of error is given by:

ME = 1.653 *\frac{7.9}{\sqrt{300}}= \pm 0.75

±0.75 ounce

4 0
3 years ago
Read 2 more answers
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