Answer:
B. ensure the production of GTP in the case of succinyl-CoA
Explanation:
Succinyl CoA like acetyl-CoA has a thioester bond with very negative free energy of hydrolysis. In this reaction, hydrolysis of the thioester bond leads to the formation of phosphoester bond with inorganic phosphate. This phosphate is transferred to histidine residue of the enzyme and this high energy unstable phosphate is finall transferred to GDP resulting in generation of GTP.
Hence the answer is B. ensure the production of GTP in the case of succinyl-CoA.
Answer: a bowling ball ...
Explanation:
Answer:
d. 1/3
Explanation:
Given, M is a dominant allele which is responsible for tailless kittens and m is recessive wild type allele which leads to kittens with tail. M is a lethal allele which means that if it is present in homozygous condition, the kitten will not survive. So the Manx cats should be heterozygous i.e. Mm.
When they mate, Mm X Mm :
M m
M MM Mm
m Mm mm
1/4 kittens will have MM genotype so they will not survive. Out of the remaining kittens, 1/3 will be mm and hence they will have normal tail. Remaining 2/3 will have Mm genotype like their parents and will be born without tail. Hence, there is 1/3 probability that one of the four kittens will have a normal tail.
Answer:
all cells have the ability to move
Explanation:
