Answer:
(3,0)
Step-by-step explanation:
7)
y = - 2x + 6
3y - x +3 =0
3(-2x+6)-x+3=0
-6x+ 18 -x+3=0
-7x+21=0
-7x+-21
x=3
y=-2(3)+6
y=-6+6
y=0
Culvert is a tunnel, therefore we can use the volume and area formula of a cylinder.
Circumference is given such as 280 cm and the circumference formula of a circle is C = 2*pi*r
Solving for the radius, we have:
280 = 2*3.14*r
r = 280/2*3.14
r = 44.59 cm
Area of one end:
Area = pi*r²
Area = 3.14 * 44.59²
Area= 6,243.2 cm²
The total area is times two of area since there were two ends in the culvert.
Total area = 6243.2 * 2
Total area = 12,486.32 cm²
Answer:
Step-by-step explanation:
As the base is a square so the length is a, width is a and the height is h.
According to the question,
a + a + h = 96
h = 96 - 2a .... (1)
Volume of the box, V = length x width x height
V = a x a x h
V = a² (96 - 2a) from equation (1)
V = 96a² - 2a³
Differentiate both sides
Now put it equal to zero.
192 a - 6a² = 0
a = 32 in
h = 96 - 2 x 32
h = 32 in
Thus, the length and the width os teh base is 32 in and the height is 32 in.
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