A) x² + y² = 327
B) x * y = 101
Solving equation B for y²
B) y² = 10,201 / x²
Substituting this into equation A)
x² + 10,201 / x² = 327
x^4 + 10,201 = 327x²
x^4 -327x² + 10,201 = 0
Using the quartic equation calculator: http://www.1728.org/quartic.htm
x1 = 17.090169943749476
x2 = 5.909830056250525
x1 * x2 = 101
x1 + x2 = 23
Hmm. I think true in this case
If you’re solving for a... subtract the 8 to the other side so...
-4(a+3)- 3(2a-8) = 22.
Distribute the -4 and -3 into the parentheses (two negatives multiplied together is a positive)...
-4a-12-6a+24 = 22.
Add the constants and a’s together.
-10a + 12 = 22
Subtract 12 to the other side.
-10a = 10
Divide both sides by -10.
a = -1
Check and make sure that this answer works with the problem.
-4(-1+3)-3(-2-8)=22
-4(-2)-3(-10)=22.
-8+30=22.
22=22, the answer checks out
Answer:
Step-by-step explanation:
We are given the function:
We want to find f(3), so we must substitute 3 in for x.
Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition, and Subtraction.
Solve the exponent first.
Multiply 8 and 3.
Add.
For the function given, f(3) is 30.
Answer:
The exact answer is 16.6666666667. Rounded would be about 17.
Step-by-step explanation:
Hope i was right and this helped!
