Question

Help help help help pls

Answer 1

Answer:

$\theta = 82.2^\circ$

Step-by-step explanation:

$Let \ \angle BAC = \theta$

Opposite = BC ,

Adjacent = AB = x = 3 ,

Hypotenuse = AC = y = 22

Using trigonometric ratios.

$sin \theta = \frac{opposite}{hypotenuse }\\\\cos \theta = \frac{adjacent}{hypotenuse}\\\\tan \theta = \frac{opposite}{adjacent}$

Since we have adjacent and hypotenuse we use cosine's  ratio

to find the angle.

           $cos \theta = \frac{x}{y} = \frac{3}{22} \\\\\theta = cos^{-1} \frac{3}{22} = 82.16 = 82.2^\circ$