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Murrr4er [49]
3 years ago
7

Cell phone plan a cost 70 per month but gives you a free 500 dollar phone plan b coat 50 dollors but has no phone. How long woul

d it take them to reach the same proce
Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
6 0

Answer:

Number of month = 25 month

Step-by-step explanation:

Given:

Plan A $70 per month and $500 phone cost

Plan B $50 per month No phone

Assume;

Number of month = x

So,

50x + 500 = 70x

20x = 500

x = 25

Number of month = 25 month

You might be interested in
Which values are with in the range of the piecewise defined function?
zepelin [54]

Answer:

y = -6; -3;  0

Step-by-step explanation:

To quickly solve this problem, we can use a graphing tool or a calculator to plot the equation.

Please see the attached image below, to find more information about the graph

The equation is:

f(x)  = 2x+2  , x < -3

f(x) = x, x = -3

f(x) = - x -2 , x > -3

From the graph, we can see that the values are

y = -6; -3;  0

4 0
3 years ago
Read 2 more answers
Two is eight less than twice a number. What is the number?
Mekhanik [1.2K]

Answer:

x = 5

Step-by-step explanation:

First, break it down:

Two is eight less than twice a number

2 = 2x - 8

+8       + 8

10 = 2x

5 = x

Hope this helps :)

3 0
3 years ago
find the smallest number of terms of the AP "-54,-52.5,-51,-49.5" ....that must be taken for the sum of the terms to be positive
wel

The smallest number of terms of the AP that will make the sum of terms positive is 73.

Since we need to know the number for the sum of terms, we find the sum of terms of the AP

<h3>Sum of terms of an AP</h3>

The sum of terms of an AP is given by S = n/2[2a + (n - 1)d] where

  • n = number of terms,
  • a = first term and
  • d = common difference

Since we have the AP "-54,-52.5,-51,-49.5" ....", the first term, a = -54 and the second term, a₂ = -52.5.

The common difference, d = a₂ - a

= -52.5 - (-54)

= -52.5 + 54

= 1.5

<h3>Number of terms for the Sum of terms to be positive</h3>

Since we require the sum of terms , S to be positive for a given number of terms, n.

So, S ≥ 0

n/2[2a + (n - 1)d] ≥ 0

So, substituting the values of the variables into the equation, we have

n/2[2(-54) + (n - 1) × 1.5] ≥ 0

n/2[-108 + 1.5n - 1.5] ≥ 0

n/2[1.5n - 109.5] ≥ 0

n[1.5n - 109.5] ≥ 0

So, n ≥ 0 or 1.5n - 109.5 ≥ 0

n ≥ 0 or 1.5n ≥ 109.5

n ≥ 0 or n ≥ 109.5/1.5

n ≥ 0 or n ≥ 73

Since n > 0, the minimum value of n is 73.

So, the smallest number of terms of the AP that will make the sum of terms positive is 73.

Learn more about sum of terms of an AP here:

brainly.com/question/24579279

#SPJ1

4 0
2 years ago
Need help vrtfv fvvfgsf
maksim [4K]

Answer:

b = 8

Step-by-step explanation:

Use the Pythagorean theorem

c^2 = a^2 + b^2  

c = 10

a = 6

b = ?

Substitute into the formula

10^2 = 6^2 + b^2      

100 = 36 + b^2            Subtract 36 from both sides

100 - 36 = b^2             Combine

64 = b^2                      Take the square root of both sides.

√64 = √b^2

b = 8

7 0
3 years ago
Lisa's test grades are 79, 89, and 90. there will be one more test this year. if lisa wants her test average to be at least 88,
erik [133]
For this case, what we are going to do first is to assume that all the exams are worth the same percentage of the final grade.
 We have then that Lisa's average grade point equation is:
 88 =  \frac{79 + 89 + 90 + x}{4}
 Where,
 x: minimum note that lisa must obtain in the last exam.
 Clearing x we have:
 x = (88 * 4) - (79 + 89 + 90)&#10;&#10;x = 94
 Answer:
 
the lowest grade she can get on her last test is:
 
x = 94
5 0
4 years ago
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