Answer: There is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.
Step-by-step explanation:
Total number of students = 8
Number of student who has passed Exam P/1 = 1
Number of student who has passed Exam FM/2 = 1
No student has passed more than one exam.
According to question, exactly three students from a randomly chose group of four students have not passed Exam P/1 or Exam FM/2.
So, Probability will be

Hence, there is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.
Answer:
56
Step-by-step explanation:
The answer is 28.09 g. I hope this helped.
Is it an inverse function
1/3+4/5= 17/15
The commun multipleof 3 and 5 is 15.
1/3×5= 5/15
4/5×3= 12/15
5/12+12/15= 17/12
17/12×7= 119/84
119/84
Hope this helps! :)
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