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lora16 [44]
3 years ago
9

Jason builds doghouses for a pet store. Each doghouse is a wooden structure with a rectangular base that has an area of 21 squar

e feet and a length that is 4 feet more than its width.
If x represents the width of the doghouse, write an equation in the given form that can be used to determine the possible dimensions of the base of the doghouse.

Mathematics
2 answers:
il63 [147K]3 years ago
7 0

Answer:

5 remainder 2

Step-by-step explanation:

divide

xxMikexx [17]3 years ago
5 0

answer: 5 with a remainder of 2

Step-by-step explanation:

divide 21 and 4

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Rx h= ax-k solve for x
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5 0
3 years ago
Write a equation to solve this problem. How much money is 6.4% of $25?
Naddik [55]
If $25 = 100%. Then
Y = 6.4%

Y = (25x6.4) /100 (Equation)

Y= $1.6

7 0
3 years ago
2y - 7+ 5y = 0<br> Step by step work
Ugo [173]

Answer:

y=1

Step-by-step explanation:

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5 0
3 years ago
Simplify the ratio 13:143
dmitriy555 [2]
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3 0
4 years ago
Read 2 more answers
Part F What is the mean absolute deviation for Doctor A’s data set on glasses? What is the mean absolute deviation for Doctor B’
frez [133]

There is more variability on glasses of doctor B's dataset than the glasses of doctor A's dataset

<h3>The doctors' mean absolute deviation on glasses</h3>

The dataset of doctor A is given as:

643 634 670 658 636 624 641 655 649 629

The dataset of doctor B is given as:

651 625 622 624 631 621 653 647 646 646

Using a statistical calculator, we have:

<u>Doctor A</u>

  • Doctor A: Mean Absolute Deviation (MAD) = 11.28
  • Doctor B: Mean Absolute Deviation (MAD) = 12

Hence, the mean absolute deviation is 11.28 for Doctor A’s and 12 for Doctor B’s data set on glasses

<h3>The variation of the two data</h3>

In a dataset, the larger the mean absolute deviations value, the larger the variation.

By comparison, 12 is greater than 11.28

Hence, there is more variability on glasses of doctor B's dataset than the glasses of doctor A's dataset

Read more about mean absolute deviation at:

brainly.com/question/3250070

#SPJ1

7 0
2 years ago
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