Answer:
Therefore, Δx=5/n, when have n intervals.
Step-by-step explanation:
From exercise we have interval [0,5]. So the length of the given interval is 5-0=5. Since all intervals [x0,x1],[x1,x2],…,[xn−1,xn] are equal in width.
We know that their width is Δx. We conclude that width of each subinterval Δx in terms of the number of subintervals n is equal 5/n.
Therefore, Δx=5/n, when have n intervals.
Answer:
a) 7/5
Step-by-step explanation:
Answer:
61
Step-by-step explanation:
154 * 2/5 = 61.6
.84 is the answer and I'm just filling up space
Answer:
3.24%
Step-by-step explanation:
Percentage error =[ (|calculated value - actual value) / actual value] x 100
calculated area = length x width
6.5 x 7.8 = 50.7
[(|50.7 - 52.4|] / 52.4] x 100 = 3,24