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m_a_m_a [10]
3 years ago
10

An assistant is in charge of ordering lunch for the monthly office meeting. For the first month, she orders ten Falafel wraps, t

wenty-five Turkey BLT sandwiches, and fifteen hot Ham and Swiss paninis for a total of $361.25. The next month, she orders fifteen Falafel wraps, thirteen Turkey BLT sandwiches, and twenty-two hot Ham and Swiss paninis for a total of $342.50. For the third month, she orders eight Falafel wraps, twenty-two Turkey BLT sandwiches, and twenty hot Ham and Swiss paninis for a total of $359. How much does each sandwich cost?
Mathematics
1 answer:
Dominik [7]3 years ago
5 0

Answer:

cost of each Falafel wraps = $6

cost of each Turkey BLT sandwiches: $8

cost of each hot Ham and Swiss paninis: $6.75

Step-by-step explanation:

Let's call:

x: cost of each Falafel wraps

y: cost of each Turkey BLT sandwiches

z: cost of each hot Ham and Swiss paninis

The information can be expressed mathematically as follows:

10x + 25y + 15z = 361.25 (eq. 1)

15x + 13y + 22z = 342.50 (eq. 2)

8x + 22y + 20z = 359 (eq. 3)

subtracting equation 2 to equation 1 multiplied by 1.5, we get:

24.5y + 0.5z = 199.375 (eq. 4)

equation 1 multiplied by 0.8:

8x + 20y + 12z = 289 (eq. 5)

subtracting equation 5 to equation 3:

2y + 8z = 70 (eq. 6)

equation 4 multiplied by 16:

392y + 8z = 3190 (eq. 7)

subtracting equation 6 to equation 7:

390y = 3120

y = 3120/390 = 8

Replacing into equation 6:

2(8) + 8z = 70

z = (70 - 16)/8 = 6.75

Replacing into equation 1:

10x + 25(8) + 15(6.75) = 361.25

x = [361.25 - 25(8) - 15(6.75)]/10 = 6

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A study was conducted to estimate the difference in the mean salaries of elementary school teachers from two neighboring states.
umka21 [38]

Answer:

(28900-30300) -2.07 \sqrt{\frac{2300^2}{10} +\frac{2100^2}{14}} = -3301.70

(28900-30300) +2.07 \sqrt{\frac{2300^2}{10} +\frac{2100^2}{14}} = 501.698

The confidence interval would be -3301.70 \leq \mu \leq 501.698 and since the confidence interval contains the value of 0 we don't have enough evidence to conclude that the difference between the two states for the salary of teachers are significantly different.

Step-by-step explanation:

We have the following info given by the problem

\bar X_1 = 28900 the sample mean for the salaries of teachers in Indiana

s_1 = 2300 the sample deviation for the salary of  teachers in Indiana

n_1 =10 the sample size from Indiana

\bar X_2 = 30300 the sample mean for the salaries of teachers in Michigan

s_2 = 2100 the sample deviation for the salary of  teachers in Michigan

n_2 =14 the sample size from Michigan

We want to find a confidence interval for the difference in the two means and the formula for this case is given by;

(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}

The degrees of freedom for this case are:

df = n_1 +n_2 -2= 10+14-2 =22

The confidence is 95%so then the significance is \alpha=0.05 and the \alpha/2 =0.025, we need to find a critical value in the t distribution with 22 degrees of freedom who accumulates 0.025 of the area on each tail and we got:

t_{\alpha/2}= 2.07

And now replacing in the formula for the confidence interval we got:

(28900-30300) -2.07 \sqrt{\frac{2300^2}{10} +\frac{2100^2}{14}} = -3301.70

(28900-30300) +2.07 \sqrt{\frac{2300^2}{10} +\frac{2100^2}{14}} = 501.698

The confidence interval would be -3301.70 \leq \mu \leq 501.698 and since the confidence interval contains the value of 0 we don't have enough evidence to conclude that the difference between the two states for the salary of teachers are significantly different.

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A 37 inch tv sells for $400. This is a $45 less than five times the cost of a 19 inch tv. Find the cost of the 19 inch tv.
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Answer:

A 19 inch tv cost $89

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37 inch tv : 400 = 5x - 45

19 inch tv : x

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5x - 45 = 400

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How much interest is earned on $2,700 in one year if it is invested at 3%?
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3% of $2,700

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