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lidiya [134]
3 years ago
15

Find the missing side lengths

Mathematics
1 answer:
SVEN [57.7K]3 years ago
8 0

Answer:

Sin \: 60=\frac{\sqrt{3} }{u}

u=\sqrt{3} /sin\:60

u=\sqrt{3} /\sqrt{3} /2

u=2

<h3>..........................</h3><h3>Cos\: 60=\frac{v}{2}</h3><h3>v=2\: cos\:60</h3><h3>v=2(\frac{1}{2})</h3><h3>v=1</h3>

<u>OAmalOHopeO</u>

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