Question

Find the missing side lengths

Answer 1

Answer:

$Sin \: 60=\frac{\sqrt{3} }{u}$

$u=\sqrt{3} /sin\:60$

$u=\sqrt{3} /\sqrt{3} /2$

$u=2$

..........................

$Cos\: 60=\frac{v}{2}$

$v=2\: cos\:60$

$v=2(\frac{1}{2})$

$v=1$

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