Question

What is the equation of a line that passes through the points (–3, 4) and (2, 8)?

Answer 1

Answer:

y = \frac{4}{5}x + \frac{32}{5}

Step-by-step explanation:

(x₁ , y₁) = (-3, 4)  & (x₂ , y₂) = (2 , 8)

Slope = $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

         $= \frac{8-4}{2-[-3]}\\\\= \frac{8-4}{2+3}\\\\= \frac{4}{5}$

m = 4/5 ;

Equation of the line: y - y₁ = m(x - x₁)

$y - 4 = \frac{4}{5}(x - [-3])\\\\y - 4 = \frac{4}{5}(x +3)\\\\y - 4 = \frac{4}{5}x + \frac{4}{5}*3\\\\ y = \frac{4}{5}x + \frac{12}{5}+4\\\\ y = \frac{4}{5}x + \frac{12}{5} + \frac{4*5}{1*5}\\\\ y =\frac{4}{5}x + \frac{12}{5} +\frac{20}{5}\\\\ y = \frac{4}{5}x + \frac{32}{5}$

Answer 2

Answer:

=5

Step-by-step explanation:

4-9= -5

2-3 = -1

=5

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