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4 years ago

12

A jet flies at a rate of 1.3 x 10^ 6 feet per hour. Written in scientific notation, which is the best estimate of how many feet

the jet will travel in 2.8 x 10^ 3 hours?

2 answers:

lapo4ka [179]4 years ago

8 0

(1.3 * 10^6)(2.8 * 10^3) = (1.3 * 2.8) = 3.64.....(10^6 * 10*3) = 10^9
3.64 * 10^9 <==

nadezda [96]4 years ago

7 0

(1.3X10^6ft/hr)(2.8X10^3hr)

(1.3*2.8)(10^6*10^3)

Rule (a^b)(a^c)=a^(b+c)

(3.64)(10^(6+3))

3.64(10^9)

3.64X10^9 ft

Technically we only had two significant figures and the answer should be:

3.6X10^9 if we were to express our answer to the correct number of significant figures....

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navik [9.2K]

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Find out the how long will it take the submarine to descend to the ocean floor

To proof

Formula

$r = \frac{d}{t}$

where d = distance traveled (or descended),

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natita [175]

Answer:

$\frac{y}{x}-2ln(\frac{y}{x}+1)=lnx+C$

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Given differential equation,

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$\implies \frac{dy}{dx}=-\frac{x^2 + y^2}{x^2 - xy}----(1)$

Let y = vx

Differentiating with respect to x,

$\frac{dy}{dx}=v+x\frac{dv}{dx}$

From equation (1),

$v+x\frac{dv}{dx}=-\frac{x^2 + (vx)^2}{x^2 - x(vx)}$

$v+x\frac{dv}{dx}=-\frac{x^2 + v^2x^2}{x^2 - vx^2}$

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$x\frac{dv}{dx}=\frac{1 + v^2}{v-1}-v$

$x\frac{dv}{dx}=\frac{1 + v^2-v^2+v}{v-1}$

$x\frac{dv}{dx}=\frac{v+1}{v-1}$

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