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VikaD [51]
3 years ago
7

How to do this question plz answer me ​

Mathematics
1 answer:
Sati [7]3 years ago
7 0

Answer:

d =  \frac{4 - 3c}{c + 1}

Step-by-step explanation:

To make d the subject of formula, we need to rearrange the equation such that we arrive at d= _____.

c =  \frac{4 - d}{d + 3}

<em>Remove the fraction by multiplying (d +3) on both sides:</em>

c(d + 3) = 4 - d

<em>Expand</em><em>:</em>

<em>cd + 3c = 4 - d</em>

<em>Bring</em><em> </em><em>all</em><em> </em><em>the</em><em> </em><em>d</em><em> </em><em>terms</em><em> </em><em>to</em><em> </em><em>one</em><em> </em><em>side</em><em> </em><em>and</em><em> </em><em>move</em><em> </em><em>the</em><em> </em><em>others</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>other</em><em> </em><em>side</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>equation</em><em>:</em>

cd + d = 4 - 3c

<em>Factorise</em><em> </em><em>d</em><em> </em><em>out</em><em>:</em>

<em>d(c + 1) = 4 - 3c</em>

<em>Divide</em><em> </em><em>by</em><em> </em><em>(</em><em>c</em><em> </em><em>+</em><em>1</em><em>)</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>:</em>

<em>d =  \frac{4 - 3c}{c + 1}</em>

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