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2 years ago

How to do this question plz answer me

Mathematics

1 answer:

Sati [7]2 years ago

7 0

Answer:

$d = \frac{4 - 3c}{c + 1}$

Step-by-step explanation:

To make d the subject of formula, we need to rearrange the equation such that we arrive at d= _____.

$c = \frac{4 - d}{d + 3}$

Remove the fraction by multiplying (d +3) on both sides:

$c(d + 3) = 4 - d$

Expand:

$cd + 3c = 4 - d$

Bring all the d terms to one side and move the others to the other side of the equation:

$cd + d = 4 - 3c$

Factorise d out:

$d(c + 1) = 4 - 3c$

Divide by (c +1) on both sides:

$d = \frac{4 - 3c}{c + 1}$

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Martina filled a 100mL container Simone filled a 1.2 liter container how much more water does Simone have than Martina

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You will get the answer in percent

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2 years ago

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Help me please, thank you.

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3 years ago

You bought a car that was $25500 and the value depreciates by 4.5% each year.

nikklg [1K]

Answer:

(a) 20256.15625

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Step-by-step explanation:

(a) There's a formula for this problem y = A(d)^t where, A is the initial value you are given, d is the growth or decay rate and t is the time period. So, in this case, as the car cost is decreasing it is a decay problem and we can write the formula as such; y = A(1-R)^t

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2 years ago

Find cos(2*ABC) 100POINTS

juin [17]

Answer:

$-\dfrac{7}{25}$

Step-by-step explanation:

Trigonometric Identities

$\cos(A \pm B)=\cos A \cos B \mp \sin A \sin B$

Trigonometric ratios

$\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}$

where:

$\theta$ is the angle
O is the side opposite the angle
A is the side adjacent the angle
H is the hypotenuse (the side opposite the right angle)

Using the trig ratio formulas for cosine and sine:

$\cos(\angle ABC)=\dfrac{3}{5}$

$\sin(\angle ABC)=\dfrac{4}{5}$

Therefore, using the trig identities and ratios:

$\begin{aligned}\implies \cos(2 \cdot \angle ABC) & = \cos(\angle ABC + \angle ABC)\\\\& = \cos (\angle ABC) \cos (\angle ABC) - \sin(\angle ABC) \sin (\angle ABC)\\\\& = \cos^2(\angle ABC)-\sin^2(\angle ABC)\\\\& = \left(\dfrac{3}{5}\right)^2-\left(\dfrac{4}{5}\right)^2\\\\& = \dfrac{3^2}{5^2}-\dfrac{4^2}{5^2}\\\\& = \dfrac{9}{25}-\dfrac{16}{25}\\\\& = \dfrac{9-16}{25}\\\\& = -\dfrac{7}{25} \end{aligned}$

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2 years ago

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How to do this question plz answer me ​

How to do this question plz answer me