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Ipatiy [6.2K]
3 years ago
11

Paul has 30$ to spend at the fair if the admission to the fair is 5$ and the rides cost 3.50 each how many rides can paul go on

Mathematics
2 answers:
const2013 [10]3 years ago
5 0

by the time Paul got into the fair he would have already paid admission with his 30 bucks meaning that he would have 25 dollars left for rides and 25 divided by 3.50 is 7.blah blah blah the rest dosent matter so Paul could go on a maximum of 7 rides

Margaret [11]3 years ago
4 0

Answer:

7

Step-by-step explanation:

Start with $30.

Subtract $5 for the admission: $30 - $5 = $25.

Now he has $25 to spend on rides. Each ride costs $3.5, so we divide $25 by $3.50.

$25/$3.50 = 7.14

Since the number of rides must be a whole number, he can go on 7 rides.

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