Paul has 30$ to spend at the fair if the admission to the fair is 5$ and the rides cost 3.50 each how many rides can paul go on

2 answers:

const2013 [10]4 years ago

5 0

by the time Paul got into the fair he would have already paid admission with his 30 bucks meaning that he would have 25 dollars left for rides and 25 divided by 3.50 is 7.blah blah blah the rest dosent matter so Paul could go on a maximum of 7 rides

Margaret [11]4 years ago

4 0

Answer:

Step-by-step explanation:

Start with $30.

Subtract $5 for the admission: $30 - $5 = $25.

Now he has $25 to spend on rides. Each ride costs $3.5, so we divide $25 by $3.50.

$25/$3.50 = 7.14

Since the number of rides must be a whole number, he can go on 7 rides.

You might be interested in

An item is regularly priced at $95. It is on sale for 80% off the regular price. How much (in dollars) is discounted from the re

IrinaVladis [17]

Answer:

76??

Step-by-step explanation:

95×0.20=19

95-19=76

3 0

3 years ago

Really could use the help

SVEN [57.7K]

c squared= a squared+b squared so c squared=25+64 so the answer would be the square root of 89. Hope this helps!!

7 0

3 years ago

A radiator contains 10 quarts of fluid, 30% of which is antifreeze. How much fluid should be drained and replaced with pure anti

likoan [24]

V30% mixture + v100% mixture = v60% mixture

0.3(10-x) + x = 0.6(10)
3 - 0.3x + x = 6
0.7x = 6 - 3
0.7x = 3
x = 3/0.7
x = 4.286 quarts

6 0

4 years ago

Read 2 more answers

Evaluate sin(Tan^-10)

Musya8 [376]

$\tan x=0$ for $x=n\pi$ , where $n$ is any integer. The inverse tangent function returns numbers between $-\dfrac\pi2$ and $\dfrac\pi2$ . The only multiple of $\pi$ in this range is 0, so $\tan^{-1}0=0$ .