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3 years ago

12

What is the average rate of change for this quadratic function for the interval

1 answer:

Bad White [126]3 years ago

8 0

Answers are C/A your welcome

☁︎☁︎☁︎☁︎☁︎☁︎☁︎☂︎☁︎

explanation: okay so first you and then after you alone d so then you wil get 73 is s no and it’ll aid so it’s also one okay and then after you do all of that you will have to see oman kama ken shi and that is how you get the answer

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Find the perimeter of the triangle with vertices A(negative 2,2,3), B(4,negative 4,3), and C(7,6,4).

gayaneshka [121]

Answer:

$P\approx 28.872\,\text{units}$

Step-by-step explanation:

We are given coordinates of each of the vertices of the triangle ABC, hence we can use the distance formula to find the lengths of each of the side.

the distance formula is generally written as:

$r = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2+(z_1-z_2)^2}$

for the side AB: A(-2,2,3) and B(4,-4,3)

$AB = \sqrt{(-2-4)^2+(2-(-4))^2+(3-3)^2}$

$AB = \sqrt{(-6)^2+(6)^2+(3-3)^2}$

$AB = \sqrt{72}$

for the side BC: B(4,-4,3) and C(7,6,4)

$BC = \sqrt{(4-7)^2+((-4)-6)^2+(3-4)^2}$

$BC = \sqrt{110}$

for the side CA: C(7,6,4) and A(-2,2,3)

$CA = \sqrt{(7-(-2))^2+(6-2)^2+(4-3)^2}$

$CA = \sqrt{98}$

Now we all the sidelengths:

to find the perimeter we need to just sum the three side lengths:

$P = AB + BC + CA$

$P = \sqrt{72} + \sqrt{110} + \sqrt{98}$

$P\approx 28.872\,\text{units}$

this is the perimeter of triangle ABC

6 0

3 years ago

Solve the equation for y<br> y +5=-(x – 3)

goldenfox [79]

Answer:

y=-x-2

Step-by-step explanation:

y+5=-(x-3)

y+5=-x+3

y=-x+3-5

y=-x-2

6 0

2 years ago

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Sindrei [870]

Answer:

x<0

Step-by-step explanation:

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1 year ago

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xz_007 [3.2K]

Answer:

bbbbbbb

Step-by-step explanation:

i hope this helps

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3 years ago

10-kg bag of cherries for $8<br><br> ___ per kg

Sophie [7]

$8.00/10 kg equals $0.80/kg

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3 years ago