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inna [77]
2 years ago
10

a pool only open when the temperature is at least 72 degrees. Which inequality represents the temperature t, when the pool is op

en?
Mathematics
1 answer:
BartSMP [9]2 years ago
5 0

Answer:

t ≥ 72

Step-by-step explanation:

The pool has to be at least 72° or MORE to open, so we are going to have a greater sign with an equal sign under indicating that the temperature has to  at least be 72° or be greater than 72°. (≥)

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How is a property tax similar to and different from an income tax?
valina [46]

Answer:

Property tax is an ad valorem tax assessed on real estate by a local government and paid by the property owner. Income tax is tax levied by a government directly on income, especially an annual tax on personal income. Both pay the government but one is for their land and the other is for money they make.

5 0
3 years ago
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Some students reported how many pets they had. The dot plot shows the data collected: A dot plot is titled Students Pets and lab
hichkok12 [17]

Answer:B

Step-by-step explanation:I just know

4 0
3 years ago
A huge ice glacier in the Himalayas initially covered an area of 454545 square kilometers. Because of changing weather patterns,
zloy xaker [14]

Answer:

t=-20ln\left(\dfrac{1}{3}\right)

Step-by-step explanation:

The relationship between A, the area of the glacier in square kilometers, and t, the number of years the glacier has been melting, is modeled by the equation.:

A=45e^{-0.05t}

We want to determine the value of t for which the area, A(t)=15 square kilometers.

15=45e^{-0.05t}\\$Divide both sides by 45\\\dfrac{15}{45} =\dfrac{45e^{-0.05t}}{45}\\\dfrac{1}{3}=e^{-0.05t}\\$Take the natural logarithm of both sides\\ln\left(\dfrac{1}{3}\right)=ln\left(e^{-0.05t}\right)\\ln\left(\dfrac{1}{3}\right)=-0.05t\\$Divide both sides by -0.05$\\t=-\dfrac{ln\left(\dfrac{1}{3}\right)}{0.05} \\=-\dfrac{ln\left(\dfrac{1}{3}\right)}{0.05}\\t=-20ln\left(\dfrac{1}{3}\right)

Therefore, the time for which the area will be 15 sqyare kilometers is:

-20 ln(1/3) years.

7 0
3 years ago
Relationship B has a greater rate than Relationship A. This graph represents Relationship A.
r-ruslan [8.4K]

The second table could represent relationship B.

Step-by-step explanation:

Step 1:

The tables give a relationship between the growth of a plant and the number of weeks it took.

To determine the rate of each table, we determine the growth of the plant in a single week.

The growth rate in a week = \frac{Difference in height}{time taken}.

Step 2:

For the given graph, the points are (4, 3) and (8, 6).

The growth rate in a week = \frac{Difference in height}{time taken} = \frac{6-3}{8-4}=\frac{3}{4}  = 0.75.

So the growth rate for relationship A is 0.75.

Step 3:

Now we calculate the growth rates of the given tables.

Table 1's growth rate in a week = \frac{Difference in height}{time taken} = \frac{3-1.2}{5-2}=\frac{1.8}{3}  = 0.6.

Table 2's growth rate in a week = \frac{Difference in height}{time taken} = \frac{4-1.6}{5-2}=\frac{2.4}{3}  = 0.8.

Table 3's growth rate in a week = \frac{Difference in height}{time taken} = \frac{2-1.5}{4-3}=\frac{0.5}{1}  =0.5.

Table 4's growth rate in a week = \frac{Difference in height}{time taken} = \frac{3.5-1.4}{5-2}=\frac{2.1}{3}  = 0.7.

Since relationship B has a greater rate than A, Table 2 is relationship B.

3 0
3 years ago
2/3 of a pizza was left over. A group of friends divided the leftover pizza into pieces each
e-lub [12.9K]

Answer:

We can't directly answer it without the number of friends, so it would need to be a variable.

A=number of friends. X= slices

2/3 ÷ a = x

6 0
3 years ago
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