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3 years ago

Use the following parallelogram to solve for the values of x and y

Mathematics

1 answer:

Xelga [282]3 years ago

8 0

X=20 Y=2 Explanation: To find Y: 45=20y+5, subtract 5 from both sides of the equal sign making 40=20y, then divide both sides of the equal sign by 20 making y=2. To find X: 80=5x-20, add 20 to both sides of the equal sign making 100=5x, then divide both sides by 5, meaning x=20

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11=12-q <br><br> Step by step in numbers

Lina20 [59]

Answer:

q = 1

Step-by-step explanation:

$11=12-q\\\\12-q=11\\\\12-12-q=11-12\\\\-q=-1\\\\\frac{-q=-1}{-1}\\\\\boxed{q=1}$

Hope this helps.

3 0

4 years ago

Please help me. thanks.

Rama09 [41]

$~~~\text{Area of triangle} = \dfrac 12 \times \text{Base} \times \text{Height}\\\\\implies 10 = \dfrac 12 \times 5 \times w\\\\\implies w =\dfrac{20}5 \\\\\implies w = 4 ~cm$

8 0

2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Csf%20%5Clim_%7Bx%20%5Cto%20%5Cinfty%7D%20%5Ccfrac%7B%5Csqrt%7Bx-1%7D-2x%20%7D%7Bx-7%7D" id=

BARSIC [14]

<h3>Answer: -2</h3>

======================================================

Work Shown:

$\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{x-1}-2x }{ x-7 }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \frac{1}{x}\left(\sqrt{x-1}-2x\right) }{ \frac{1}{x}\left(x-7\right) }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \frac{1}{x}*\sqrt{x-1}-\frac{1}{x}*2x }{ \frac{1}{x}*x-\frac{1}{x}*7 }\\\\\\$

$\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x^2}}*\sqrt{x-1}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x^2}*(x-1)}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x}-\frac{1}{x^2}}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \frac{ \sqrt{0-0}-2 }{ 1-0 }\\\\\\\displaystyle L = \frac{-2}{1}\\\\\\\displaystyle L = -2\\\\\\$

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Explanation:

In the second step, I multiplied top and bottom by 1/x. This divides every term by x. Doing this leaves us with various inner fractions that have the variable in the denominator. Those inner fractions approach 0 as x approaches infinity.

I'm using the rule that

$\displaystyle \lim_{x\to\infty} \frac{1}{x^k} = 0\\\\\\$

where k is some positive real number constant.

Using that rule will simplify the expression greatly to leave us with -2/1 or simply -2 as the answer.

In a sense, the leading terms of the numerator and denominator are -2x and x respectively. They are the largest terms for each, so to speak. As x gets larger, the influence that -2x and x have will greatly diminish the influence of the other terms.

This effectively means,

$\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{x-1}-2x }{ x-7 } = \lim_{x\to\infty} \frac{ -2x }{ x} = -2\\\\\\$

I recommend making a table of values to see what's going on. Or you can graph the given function to see that it slowly approaches y = -2. Keep in mind that it won't actually reach y = -2 itself.

5 0

3 years ago

A large helium balloon is tethered to the ground by two cables. One cable is 100 feet long and forms an 80 degree angle with the

liraira [26]

Hey there :)

Answer attached in image. Check!

~Benjemin360

6 0

3 years ago

Find the measures of the indicated angles pictures included!!!

vazorg [7]

Answer:

Step-by-step explanation:

The angles b and 65 are complementary, meaning they sum to 90 degrees. You know this because those 2 angles and the right angle are sitting on a straight line. So, together they equal 180 and 180-90 is 90. Therefore, angle b+65 must equal 90. So, simply subtract 65 from 90 to get the answer, 25.

3 0

3 years ago