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2 years ago

Let v=-9i+j and w=-i-6j find 8v-6w

Mathematics

1 answer:

hram777 [196]2 years ago

7 0

Answer:

78i+52j

Step-by-step explanation:

8(9i+2j)-6(-i-6j)

72i+16j+6i+36j

=78i+52j

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PLEASE HELP

katovenus [111]

Answer:

$593.26

Step-by-step explanation:

We know that the price of the laptop is $2500 and each year its resale value decreases by 25%. It means that 100 - 25 = 75% of the value is retained every year for the resale.

So, the resale value for 1st year = $\frac{75}{100} *2500 =$ $1875

for 2nd year = $\frac{75}{100} *1875 =$ $1406.25

for 3rd year = $\frac{75}{100} *1406.25 =$ $1054.7

for 4th year = $\frac{75}{100} *1054.7 =$ $791.01

for 5th year = $\frac{75}{100} *791.01 =$ $593.25

Or we can use the following formula to find its resale value after 5 years:

$2500*(0.75)^5 =$ $593.26

4 0

3 years ago

Is 15/28 equivalent to 25/45

Lana71 [14]

No, it's not.

15/28 equals to (about) 0.54 while 25/45 is (about) 0.56.
They are close, but not equivalent.

7 0

3 years ago

Rewrite this expression as a power of the given number. 4^2 = 2^

Mnenie [13.5K]

The answer is 2^4, since 4^2 is 16, 2•2=4 4•2=8 8•2=16

4 0

3 years ago

Read 2 more answers

Elisa says, "If you subtract 14 from my number and multiply the difference by -3 , the result is -33 ." What is Elise's num

Svetach [21]

Answer:

Step-by-step explanation:

(x-14)*-3 = -33

-3x+42 = -33

-3x = -33-42

-3x = -75

x=25

6 0

3 years ago

Joshua is 1.45 meters tall. At 2 p.m., he measures the length of a tree's shadow to be 31.65 meters. He stands 26.2 meters away

Lena [83]

Answer:

The height of the tree=8.42 m

Step-by-step explanation:

We are given that

Height of Joshua, h=1.45 m

Length of tree's shadow, L=31.65 m

Distance between tree and Joshua=26.2 m

We have to find the height of the tree.

BC=26.2 m

BD=31.65m

CD=BD-BC

CD=31.65-26.2=5.45 m

EC=1.45 m

All right triangles are similar .When two triangles are similar then the ratio of their corresponding sides are equal.

$\triangle ABD\sim \triangle ECD$

$\frac{AB}{EC}=\frac{BD}{CD}$

Substitute the values

$\frac{AB}{1.45}=\frac{31.65}{5.45}$

$AB=\frac{31.65\times 1.45}{5.45}$

$AB=8.42m$

Hence, the height of the tree=8.42 m

6 0

3 years ago