-4x-3y-9=0
|| m1 = - ( - 4)/-3= - 4/3
_|_ m2 = -1/m1= 3/4
2x+4y-3=0
|| m1= -2/4= -1/2
_|_ m2= 2
12x-y-17=0
|| m1= -12/-1=12
_|_ m2 = -1/12
x-y=0
|| m1= -1/-1=1
_|_ m2= -1
8x - 3y - 2=0
|| m1= -8/-3= 8/3
_|_ m2 = -3/8
-2x + y - 5=0
|| m1= -(-2)/1=2
_|_ m2= -1/2
This is a system of equations. We solve it by setting it up so that when we add the two equations together, one of the variables will cancel out. We can do this by multiplying the bottom equation by 3. This will make our system of equations equal:
3a + b + 225
-3a + 3b = 75
Now we add these two equations together, because the a terms will cancel out.
4b = 300.
We can find what b is by dividing both sides by 4.
b = 75
Next, we plug in b in one of the equations and solve for a. You can use either equation, but I will use the second.
75 - a = 25
Subtract 25 from both sides and add a to both sides:
a = 50
So, the first option is correct. A = 50 and b = 75.
Answer:
170m
Step-by-step explanation:
The answer to the above question is letter d which is 170 m. To get the 170 m, kindly check the below solution:
x^2 + 13x = 1764 so x = -49 and 36, we take 36 as its the positive value. And the other side is 49. Now use 2(l+b) to find perimeter. You get (36+49)*2 = 170
Answer:
The correct option is B.
Step-by-step explanation:
The given equation is
..... (1)
Where, y is distance from home for an ant t minutes after starting out from a location near its home.
The slope intercept form of a line is
.... (2)
Where, m is slope and b is y-intercept or initial value.
On comparing (1) and (2), we get
Here, 5 represent the initial distance of ant from its home.
It means the ant is moving at 2 feet per minute and the ant started out 5 feet from its home.
Therefore option B is correct.
