Which of the following are mutually exclusive events?

Which expression is equivalent to 1/3 divided by 1/6

leonid [27]

Answer:

The answer is A

Step-by-step explanation:

cross mutliply

1×6=6

1×3=3

divide the answers

result: 2

I hope this helps

5 0

2 years ago

Ali and Tibor get paid $9 per hour. This week, Tibor made an additional $27 in overtime.

Leviafan [203]

9a + (9t+27)=x

To write it another way you could flip the numbers around:

(9t+27)+9a=x

Or flip the variable to the other side.

x=9a + (9t+27)

Any way you put the numbers as long as x is on the either side, you will get the same answer.

Hope this helps!

4 0

3 years ago

What shape is a rhombus related to and why

Ksju [112]

A rhombus is related to a “Parallelogram”

Why? - because it fulfills the requirements of a parallelogram: a quadrilateral with two pairs of parallel sides. It goes above and beyond that to also have four equal-length sides, but it is still a type of parallelogram.

hope this helped <3

8 0

3 years ago

Andrew has a cell phone plan that provides 300 free minutes each month for

Mekhanik [1.2K]

Answer:

Andrew has a cell phone plan that provides 300 free minutes each month for a flat rate of $19. For any minutes over 300, Andrew is charged $0.39 per minute. Let x be the number of minutes Andrew uses per month and f(x) be the charges based on Andrew's cell phone plan. If then If then first 300 minutes are free and each minute of next (x-300) minutes costs $0.39, therefore Hence, { 19 + 0.39(x - 300), x > 300

Hoped I helped

4 0

3 years ago

A machine that fills beverage cans is supposed to put 12 ounces of beverage in each can. The standard deviation of the amount in

erica [24]

Answer:

$\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54$

The degrees of freedom are:

$df=n-1=10-1=9$

Now we can calculate the p value using the alternative hypothesis:

$p_v =2*P(\chi^2 >13.54)=0.279$

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

Step-by-step explanation:

Assuming the following data:"12.14 12.05 12.27 11.89 12.06

12.14 12.05 12.38 11.92 12.14"

We can calculate the sample deviation with this formula:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$n=10$ represent the sample size

$\alpha=0.05$ represent the confidence level

$s^2 =0.0217$ represent the sample variance

$\sigma^2_0 =0.12^2= 0.0144$ represent the value to verify

Null and alternative hypothesis

We want to determine whether the standard deviation differs from 0.12 ounce, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 = 0.0144$

Alternative hypothesis: $\sigma^2 \neq 0.0144$

The statistic can be calculated like this;

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

$\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54$

The degrees of freedom are:

$df=n-1=10-1=9$

Now we can calculate the p value using the alternative hypothesis:

$p_v =2*P(\chi^2 >13.54)=0.279$

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

7 0

3 years ago