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3 years ago

6

eli is going to make apple pie he buys 17 apples and put them and put the in paper bags to take home each bag holds 6 apples how

many bags eli completely fill? how many appels are left

1 answer:

Natalija [7]3 years ago

5 0

Answer:

Eli can only have 2 bags, and there will be 5 apples left

Step-by-step explanation:

17/6=2 with a remainder of 5

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Will give brainliest, please help fast

Gekata [30.6K]

Answer:

Converting the equation $x^2-20x+13=0$ into completing the square method we get: $\mathbf{(x-10)^2=87}$

Step-by-step explanation:

we are given quadratic equation: $x^2-20x+13=0$

And we need to convert it into completing the square method.

Completing the square method is of form: $a^2-2ab+b^2=(a-b)^2$

Looking at the given equation $x^2-20x+13=0$

We have a = x

then we have middle term 20x that can be written in form of 2ab So, we have a=x and b=? Multiplying 10 with 2 we get 20 so, we can say that b = 20

So, 20x in form of 2ab can be written as: 2(x)(10)

So, we need to add and subtract (10)^2 on both sides

$x^2-20x+13=0\\x^2-2(x)(10)+(10)^2-(10)^2+13=0\\(x^2-2(x)(10)+(10)^2) \:can\: be\: written\: as\: (x-10)^2 \\(x-10)^2-100+13=0\\(x-10)^2-87=0\\(x-10)^2=87$

So, converting the equation $x^2-20x+13=0$ into completing the square method we get: $\mathbf{(x-10)^2=87}$

4 0

3 years ago

Suppose that pollution in a neighborhood comes from two factories, with marginal benefit curves given by MB1 = 12 – P1 and MB2 =

makkiz [27]

The two factors are 2 and p=10 so I used your equations and

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3 years ago

Two number cubes are rolled for two separate events:

MatroZZZ [7]

Let us first make the sample space for the event A. The Sample Space will be:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5)

(5,1) (5,2) (5,3) (5,4)

(6,1) (6,2) (6,3)

As can be clearly seen the Sample Space for the event A has 30 elements in it.

Now, it is given in the question that the event A has already occurred and we need to find the probability of the event B occurring <u><em>given that the event A has already occurred.</em></u>

Now, as we can see, from the sample space, only 11 events out of the 30 are the events of interest to us. This is shown in bold below:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5)

(5,1) (5,2) (5,3) (5,4)

(6,1) (6,2) (6,3)

Thus, the probability that the event B occurs given that the event A has already occurred is:

$P(B|A)=\frac{11}{30}\approx0.367$

In percentage the required probability is 36.7% approximately.

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3 years ago

If 7x+10=44, what is the value of 7x-50?

Daniel [21]

Answer:

-16

Step-by-step explanation:

So let’s solve for 7x. So 7x=34. So 7x-50 is 34-50 or -16

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3 years ago

According to government data, the probability that an adult was never in a museum is 15%. in a random survey of 10 adults, wh

CaHeK987 [17]

<span>Let p be the probability that an adult was never in a museum. Hence p = 0.15. Then q is the probability that an adult was in a museum is 1 - 0.15 = 0.75. We have a binomial expansion where the probability of k success in n trials is given by P_n(k) = (n, k) p^(k) q^(n -k) where (n, k) is the number of ways to select 10 objects from k things. At least two or fewer means we have P_10 (< or equal to 2) So we have P_10 (less than or equal to 2) = P_10 ( 0) + P_10 (1) + P_10 (2). So we have P _10 (0) = ( 10, 0) (0.15)^ (0) (0.75)^(0) = 0.196. For P_10(1), we have 0.3474 and for P_10(2), we have 0.2758. Adding these we have 0.1960 + 0.3474 + 0.2758 = 0.8192.</span>

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3 years ago