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amm1812
3 years ago
9

Will give brainliest, please help fast​

Mathematics
1 answer:
Gekata [30.6K]3 years ago
4 0

Answer:

Converting the equation x^2-20x+13=0 into completing the square method we get: \mathbf{(x-10)^2=87}

Step-by-step explanation:

we are given quadratic equation: x^2-20x+13=0

And we need to convert it into completing the square method.

Completing the square method is of form: a^2-2ab+b^2=(a-b)^2

Looking at the given equation x^2-20x+13=0

We have a = x

then we have middle term 20x that can be written in form of 2ab So, we have a=x and b=? Multiplying 10 with 2 we get 20 so, we can say that b = 20

So, 20x in form of 2ab can be written as:  2(x)(10)

So, we need to add and subtract (10)^2 on both sides

x^2-20x+13=0\\x^2-2(x)(10)+(10)^2-(10)^2+13=0\\(x^2-2(x)(10)+(10)^2) \:can\: be\: written\: as\: (x-10)^2 \\(x-10)^2-100+13=0\\(x-10)^2-87=0\\(x-10)^2=87

So, converting the equation x^2-20x+13=0 into completing the square method we get: \mathbf{(x-10)^2=87}

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