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Komok [63]
2 years ago
9

Can anyone explain how you graph things for example, like y=x-4 how would you graph that

Mathematics
1 answer:
Savatey [412]2 years ago
8 0

Answer:

In basicallity if a question such as this pops up, the correct way to go would first be to graph this. y=x-4 would be equivalent to x=4.

My paper work is below:

y = x - 4

0 = x - 4

-x = -4

x = 4

Hope this helped..

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Answer:

8,101\ bears

Step-by-step explanation:

we know that

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y=a(b)^{x}

where

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a ----> is the initial value

b ---> is the base

step 1

Find the value of a

For x=0 (year 2009)

y=1,570 bears

substitute

1.570=a(b)^{0}

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y=1.570(b)^{x}

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Find the value of b

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y=1,884 bears

substitute

1,884=1.570(b)^{1}

b=1,884/1.570

b=1.2

The exponential function is equal to

y=1.570(1.2)^{x}

step 3

How many bears will there be in 2018?

2018-2009=9 years

so

For x=9 years

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y=1.570(1.2)^{9}

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Answers in Scientific Notation.
dmitriy555 [2]

one way is to factor the expressions

(a)

10^{5} (1.2 + (5.35 × 10^{1}))

= 10^{5} (1.2 + 53.5)

= 54.7 × 10^{5} = 5.47 × 10^{1}× 10^{5} = 5.47 × 10^{6}

(b)

10^{-3}((6.91 × 10^{1}) + 2.4)

= 10^{-3}(69.1 + 2.4)

= 71.5 × 10^{-3} = 7.15 × 10^{1} × 10^{-3} = 7.15 × 10^{-2}

(c)

10^{5}((9.7 × 10^{1}) + 8.3)

= 10^{5}(97 + 8.3)

= 105.3 × 10^{5} = 1.053 × 10^{2} × 10^{5} = 1.053 × 10^{7}

(d)

10^{1}((3.67 × 10^{1}) - 1.6)

= 10^{1}(36.7 - 1.6)

= 35.1 × 10^{1} = 3.51 × 10^{1} × 10^{1} = 3.51 × 10^{2}

(e)

10^{-6}((8.41 × 10^{1}) - 7.9)

= 10^{-6}(84.1 - 7.9 )

= 76.2 × 10^{-6} = 7.62 × 10^{1} × 10^{-6} = 7.62 × 10^{-5}

(f)

10^{4}((1.33 × 10^{1}) - 4.9 )

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7 0
3 years ago
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