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mrs_skeptik [129]
3 years ago
8

Find the slope of the line through each pair of points.

Mathematics
1 answer:
Kryger [21]3 years ago
3 0

1. -0.5

2. -1.5

3. 1.75

4. -5/3

5. -37/30

6. 1.35

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A bag has 3 white scraps,2 yellow scrapes,and 3 black scraps.You randomly pull a scrap from the bag,keep it out,and then pull ou
WINSTONCH [101]

Answer:

25/56

Step-by-step explanation:

Prob of white = 3/8

Probability of not white = 1 - 3/8

= 5/8

Second pick without replacement

Probability of white = 2/7

Probability of not white = 1 - 2/7

= 5/7

Total probability = 5/8 x 5/7

= 25/56

5 0
3 years ago
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Need an answer, please need an answer, please​
inna [77]

Answer:

Step-by-step explanation:

O

3x² - 11x - 4 = 0

a = 3 ; b = -11 , c = -4

Sum \ of \ roots = \dfrac{-b}{a}=\dfrac{-(-11)}{3}=\dfrac{11}{3}\\\\Product \ of \ roots =\dfrac{c}{a}=\dfrac{-4}{3}\\\\

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8x² + 12x = -1

8x² + 12x + 1 = 0

a = 8 ;  b = 12 ; c = 1

Sum  \ of \ roots =\dfrac{-b}{a}=\dfrac{-12}{8}=\dfrac{-3}{2}\\\\Product \ of \ roots = \dfrac{c}{a}=\dfrac{1}{8}

L

x² + x = 6

x² + x - 6 = 0

a = 1 ; b= 1 ; c = -6

Sum \ of \ roots = \dfrac{-1}{1}=-1\\\\Product \ of \ roots = \dfrac{-6}{1}=-6

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x²- 2x - 2 =0

a = 1 ; b = -2 ; c = -2

Sum \ of \ roots = \dfrac{-(-2)}{1}=2\\\\Product \ of \ roots = \dfrac{-2}{1}=-2

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4x - 5 = -4x²

4x² + 4x - 5 = 0

a = 4 ;  b = 4 ; c = -5

Sum \ of \ roots = \dfrac{-4}{4}=-1\\\\Product \ of \  roots=\dfrac{-5}{4}

B

12x² +x -6 = 0

a = 12 ; b = 1 ; c = -6

Sum \ of \ roots =\dfrac{-1}{12}\\\\Product \ of \ roots  =\dfrac{-6}{12}=\dfrac{-1}{2}

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2x² + 5x - 25 = 0

a = 2 ; b = 5 ; c = -25

Sum \ of \ roots=\dfrac{-5}{2}\\\\Product \ of \ roots =\dfrac{-25}{2}

A

6x² -5x - 4 = 0

a = 6 ; b = -5 ; c = -4

Sum \ of \ roots =\dfrac{-[-5]}{6}=\dfrac{5}{6}\\\\Product \ of \ roots = \dfrac{-4}{6}=\dfrac{-2}{3}

8 0
2 years ago
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Express this to single logarithm
zzz [600]

Answer:  \log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right)

We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.

===========================================================

Explanation:

It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.

I'm going to use these three log rules, which apply to any base.

  1. log(A) + log(B) = log(A*B)
  2. log(A) - log(B) = log(A/B)
  3. B*log(A) = log(A^B)

From there, we can then say the following:

\frac{1}{2}\log_{2}\left(m\right)-3\log_{2}\left(n\right)+2\log_{2}\left(q\right)\\\\\log_{2}\left(m^{1/2}\right)-\log_{2}\left(n^3\right)+\log_{2}\left(q^2\right) \ \text{ .... use log rule 3}\\\\\log_{2}\left(\sqrt{m}\right)+\log_{2}\left(q^2\right)-\log_{2}\left(n^3\right)\\\\\log_{2}\left(\sqrt{m}*q^2\right)-\log_{2}\left(n^3\right) \ \text{ .... use log rule 1}\\\\\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right) \ \text{ .... use log rule 2}

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3 years ago
What is the answer to ax-8b=c
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Brooke multiplied 3 and 9 and got 17. Brooke knows her answer is wrong because she knows is should be approximately
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Answer: 3 times 9 is 27

Step-by-step explanation:

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