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Ghella [55]
3 years ago
15

Question #2 What is the difference?​

Mathematics
1 answer:
e-lub [12.9K]3 years ago
3 0

Answer:

B  \frac{b-10}{b-1}

Step-by-step explanation:

In order to get the same denominator, we need to multiply the second fraction by (b+2) in the numerator and denominator.

We will end up in something like this :\frac{b^{2} - 2b - 8 -6(b+2) }{(b-1)(b+2)}

I just timed the second fraction by b+ 2 and then i added them together.

Therefore, we will get \frac{b^{2} - 8b - 20}{(b-1)(b-2)}

now factoring the numerator we will end like this

\frac{(b-10)(b+2)}{(b-1)(b+2)}

we will then end up with the answer.

Hope this helps.

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Please help me find the length of EC
harina [27]

Answer:

15

Step-by-step explanation:

BD=AC

E is the midpoint of both lines, so BE=CE

6 0
3 years ago
Anybody know the answer I need help. Please
Evgen [1.6K]

Answer:

  \dfrac{p^2+9p+2}{p^2-49}

Step-by-step explanation:

Problems like this require that you recognize that the denominator of the right term is a factor of the denominator of the left term. That is, you're supposed to know how to recognize and factor the difference of two squares.

  \dfrac{5-p}{49-p^2}+\dfrac{p+1}{p-7}=\dfrac{p-5}{p^2-49}+\dfrac{p+1}{p-7}\\\\=\dfrac{p-5}{(p-7)(p+7)}+\dfrac{p+1}{p-7}\cdot\dfrac{p+7}{p+7}\\\\=\dfrac{(p-5)+(p+1)(p+7)}{(p-7)(p+7)}=\dfrac{p-5+p^2+8p+7}{p^2-49}=\dfrac{p^2+9p+2}{p^2-49}

8 0
3 years ago
Please show your work.​
Nastasia [14]

Answer:

1. 8.19, 2. 25.96, 3. 3.95

Step-by-step explanation:

use soh cah toa

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28cos73=x=8.186

2. sin is opposite over hypotenuse

sin68=x/28

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28sin68=x=25.961

3. sin is opposite over hypotenuse

sin26=x/9

myltiply both sides by 9

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8 0
3 years ago
Is it ok you guys maybe do this one too sorry...<br> (−6)(−0.4)(−0.5)
olchik [2.2K]
(-6)(-0.4)(-0.5) = (-1)6⋅4⋅5⋅10⁻² = -1.2
5 0
3 years ago
Which algebraic expressions are polynomials? Check all that apply. PLEASE HELP
dexar [7]
Selections 2, 3, 5, 6 are polynomials.

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3 0
3 years ago
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