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const2013 [10]
2 years ago
12

Suppose one bag contains 500 cubic inches of confetti. How many bags will Student Government need to fill 100 containers? If the

y need 100 containers, how many TOTAL cubic inches of confetti will they need?
type your answer...
cubic inches How many bags will they need if each bag contains 500 cubic inches of confetti? You cannot buy a partial bag of confetti.

type your answer...
bags
Mathematics
1 answer:
Vanyuwa [196]2 years ago
5 0

The number of bags that they will need if each bag contains 500 cubic inches of confetti is 20,000

<h3>How to find the total volume ?</h3>

One bag contains 500 cubic inches of confetti.

Therefore,

1 bag = 500 inches³

The student need to fill 100 containers with the bag.

Each container can accomodates 100,000 cubic inches.

Therefore,

1 bag = 500 inches³

100,000inches³ = 1 container = 200 bags

Therefore,  

100 containers will contain 20, 000 bags of confetti.

learn more on volume here: brainly.com/question/10224096

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I know this because my crush is Jewish, is that bad lol?
8 0
3 years ago
Dan invests £800 into his bank account.
Ronch [10]

Answer:

£160

Step-by-step explanation:

Ammount he receives per year times 4.

800 x 0.05 x 4

= £160

6 0
3 years ago
Show work please<br> \sqrt(x+12)-\sqrt(2x+1)=1
Nesterboy [21]

Answer:

x=4

Step-by-step explanation:

Given \displaystyle\\\sqrt{x+12}-\sqrt{2x+1}=1, start by squaring both sides to work towards isolating x:

\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2

Recall (a-b)^2=a^2-2ab+b^2 and \sqrt{a}\cdot \sqrt{b}=\sqrt{a\cdot b}:

\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2\\\implies x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1

Isolate the radical:

\displaystyle\\x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1\\\implies -2\sqrt{(x+12)(2x+1)}=-3x-12\\\implies \sqrt{(x+12)(2x+1)}=\frac{-3x-12}{-2}

Square both sides:

\displaystyle\\(x+12)(2x+1)=\left(\frac{-3x-12}{-2}\right)^2

Expand using FOIL and (a+b)^2=a^2+2ab+b^2:

\displaystyle\\2x^2+25x+12=\frac{9}{4}x^2+18x+36

Move everything to one side to get a quadratic:

\displaystyle-\frac{1}{4}x^2+7x-24=0

Solving using the quadratic formula:

A quadratic in ax^2+bx+c has real solutions \displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}. In \displaystyle-\frac{1}{4}x^2+7x-24, assign values:

\displaystyle \\a=-\frac{1}{4}\\b=7\\c=-24

Solving yields:

\displaystyle\\x=\frac{-7\pm \sqrt{7^2-4\left(-\frac{1}{4}\right)\left(-24\right)}}{2\left(-\frac{1}{4}\right)}\\\\x=\frac{-7\pm \sqrt{25}}{-\frac{1}{2}}\\\\\begin{cases}x=\frac{-7+5}{-0.5}=\frac{-2}{-0.5}=\boxed{4}\\x=\frac{-7-5}{-0.5}=\frac{-12}{-0.5}=24 \:(\text{Extraneous})\end{cases}

Only x=4 works when plugged in the original equation. Therefore, x=24 is extraneous and the only solution is \boxed{x=4}

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2 years ago
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MArishka [77]
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3 years ago
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8 0
3 years ago
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