3 years ago

Linear functions take the shape of a...

1 answer:

maks197457 [2]3 years ago

7 0

Answer:Las funciones lineales se representan con una línea recta en el plano cartesiano. ... Cuando a los cambios iguales de una variable independiente le corresponden variaciones iguales de la variable dependiente, se habla de función lineal.

Step-by-step explanation :

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Determine the equation of the inverse of:<br> f(x) = 5x^2+ 80x – 15

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Answer:

2343Sfvdawruit5788888888888888

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3 years ago

Solve the equation. x2 = 160

zhannawk [14.2K]

80 because 160 divided by 2 is 80 so 2 x 80

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3 years ago

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The graph of a linear function passes through the points (2, 4) and (8, 10).

Keith_Richards [23]

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 2}}\quad ,&{{ 4}})\quad 
% (c,d)
&({{ 8}}\quad ,&{{ 10}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
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\begin{array}{llll}
\textit{plug in the values for }
\begin{cases}
y_1=4\\
x_1=2\\
m=\boxed{?}
\end{cases}\\
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3 years ago

If she was vaping every 15 minutes, assuming she was awake from 7 am- 11 pm (16 hours) how many times in a day would she vape?

Ray Of Light [21]

Answer:

64 times

Step-by-step explanation:

16 hours to minutes: 16*60 = 960 minutes

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2 years ago

Complex numbers zj and zz are given by zj = 3- j2, zz = - 4 + j3. (a) express zj and zz in polar form. (b) find lz1l by first ap

inna [77]

Solution:

Given: zj = 3- j2, zz = - 4 + j3

Part a:

zj = 3- j2 = $3.6e^{-j33.7^{\circ}}$

zz = - 4 + j3 = $5e^{j143.1^{\circ}}$

Part b:

|zj| = |3− j2| = √3² +(−2)² = √13 = 3.60

|z1| = √(3− j2)(3+ j2) = √ 13 = 3.60.

Part c:

With the help of part a:

z1z2 = $3.6e^{-j33.7^{\circ}}.5e^{j143.1^{\circ}}$

6 0

3 years ago