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s2008m [1.1K]
4 years ago
7

Write two expressions whose sum is x-3/x+2, I need help it is confusing for me.

Mathematics
1 answer:
lara [203]4 years ago
6 0
\bf \cfrac{x}{x+2}~~-~~\cfrac{3}{x+2}\impliedby \textit{since the LCD is }x+2\implies \cfrac{x-3}{x+2}
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The diameter of a circle is 12 in. Find the circumference to the nearest tenth <br> please helppp
Alex_Xolod [135]

Answer:

37.68in

Step-by-step explanation:

circumference = 2πr

r= radius = diameter/2 = 12/2 =6 in

C= 2πr = 2 x 3.14 x 6= 37.68in

4 0
3 years ago
Math help please sighh &gt;.&lt; (4 options included)
Elena-2011 [213]
The answer is the third option with 2/3 as the slope.

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4 0
4 years ago
Find the value of x of this figure.
Bingel [31]
The sum of angles in a triangle is 180°
So:
(x+7) + (11x-9) +32 = 180
 15x +30 = 180
15x = 180-30
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7 0
4 years ago
stacey made 8 necklaces in 48 minutes. nick made 4 necklaces in 24 minutes. is the rate at which they made necklaces equivalent.
Bingel [31]

Answer:

Yes.

Step-by-step explanation:

Divide - 48 / 8 which equals 6. Stacey makes 6 necklaces in 1 minute. Then, do 24 / 4. This also equals 6. Nick makes 6 necklaces in one minute. Therefore, their speed is equivalent.

8 0
3 years ago
Read 2 more answers
19. The marked price of an oven is 30% above its cost. In a sale, it is
yaroslaw [1]

a) Marked price: $884, Cost: $680

b) 2.5 %

Step-by-step explanation:

a)

Let's call:

P = marked price of the oven

C = cost of the oven

We know that:

- The marked price of the oven is 30% above the cost, which means

P=(1+\frac{30}{100})C=1.30C (1)

- In the sale, the oven is sold at a discount of 25% on its marked price; so the price of the sale is (we call it S)

S=(1-\frac{25}{100})P=0.75P (2)

- We also know that the discount, which is the difference between the makerd price (P) and the discounted price (S) is

P-S=\$221 (3)

Substituting (2) into (3) we find marked price

P-0.75P=\$221\\0.25P=\$221\\P=\frac{221}{0.25}=\$884

Therefore, the cost of the oven is (from eq(1)):

C=\frac{P}{1.30}=\frac{884}{1.30}=\$680

b)

The percentage loss in this situation is given by the difference between cost of the oven and the final price at which the oven is sold.

In this case, we have:

C = $680 (cost of the oven)

The discounted prices is S, and can be f ound using eq(3):

S=P-221=884-221=\$663

Therefore, the oven costs 680$ but it is sold at 663$.

Therefore, we can calculate the percentage loss using the equation:

Loss=\frac{C-S}{C}\cdot 100 = \frac{680-663}{680}\cdot 100 =0.025\cdot 100 = 2.5\%

So, a percentage loss of 2.5%.

4 0
3 years ago
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